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Drupady [299]
3 years ago
12

Each ___ real number has no real square root. What is the answer on the line?​

Mathematics
1 answer:
Ksivusya [100]3 years ago
6 0

Answer:

Negative. Negative numbers don't have real square roots since a square is either positive or 0. The square roots of numbers that are not a perfect square are members of the irrational numbers

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4 days I have 140 copies of a book, 9 days I only have 50 left. Write an equation where c(t)=my+b where c is number of copies st
alexandr402 [8]

Answer:

c(t)=-18t+212.

Step-by-step explanation:

We have been given that 4 days I have 140 copies of a book, 9 days I only have 50 left. We are asked to write an equation c(t)=my+b, where c is number of copies still on hand and t days being available.

We have two points on line (4,140) and (9,50). Now, we will use these points to find slope as:

m=\frac{140-50}{4-9}

m=\frac{90}{-5}

m=-18

Now, we will use point-slope form of equation y-y_1=m(x-x_1) and substitute m=-18 and coordinates of point (9,50) as:

y-50=-18(x-9)

y-50=-18x+162

y-50+50=-18x+162+50

y=-18x+212

Therefore, our required equation would be c(t)=-18t+212.

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Step-by-step explanation:

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find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9). (2, -7) (1, -4) (1, -2)
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M(x, y) = ((x1 + x2)/2, (y1 + y2)/2) = ((-2 + 4)/2, (5 - 9)/2) = (2/2, -4/2) = (1, -2)
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Please help! <br> Simplify. Your answer should contain only positive exponents.
maxonik [38]

Answer:

\frac{1}{4k^3}

Step-by-step explanation:

It's already in a form that only ha positive exponents.  Just to state it though you could rewrite it as k*(4k^{4})^{-1} or k*4^{-1}*k^{-4}  The question asks for positive exponents though so yu don't need to do that.

You also need to know \frac{x^a}{x^b}=x^{a-b} so in this case \frac{k}{k^4}=\frac{k^1}{k^4} =k^{1-4}=k^{-3}=\frac{1}{k^3}

so \frac{k}{4k^4}=\frac{1}{4}*\frac{k}{k^4}=\frac{1}{4}*\frac{1}{k^3}=\frac{1}{4k^3}

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Identify the correct equation for the graph below.
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i think it is c

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