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Brums [2.3K]
2 years ago
14

If a sphere has a volume of 9198.1 in, what is the radius of the sphere?

Mathematics
1 answer:
KonstantinChe [14]2 years ago
5 0

Answer:

13

Step-by-step explanation:

Volume to find radius: (3\frac{V}{4\pi})^1^/^3

Substitute: (3\frac{9198.1}{4\pi})^1^/^3

Solve: (3(732.3))^1^/^3

2196.9^1^/^3

13≈r

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Help thank you
Valentin [98]

Answer:

(1,3)

Step-by-step explanation:

3 > -2(1)+ 3 < 4

3 > -2 + 3 < 4

3 > 1 < 4

7 0
3 years ago
BRAINLIEST NEED HELP ASAP ALOT OF POINNTS
jeka57 [31]

Answer:I believe it is -4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%2Bh%7D%7B9%7D%2B%5Cfrac%7Bh-1%7D%7B3%7D%3D%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1"
yKpoI14uk [10]

Step-by-step explanation:

Multiply both sides by 9 and you will get

2 + h + 3(h - 1) = 3

or

2 + h + 3h - 3 = 3

Solving for h, we get

4h = 4 \Rightarrow h = 1

6 0
2 years ago
material composed of two or more elements or compounds that are physically mixed together but not chemically combined whats the
Softa [21]
A material made of two or more compounds where the components aren't chemically combined is called a mixture. They both keep their individual chemical properties and their chemical makeup isn't affected by the combination.

Hope this helps!
4 0
3 years ago
Please help I don't know how to do this!
netineya [11]
<span>Constraints (in slope-intercept form)
x≥0,
y≥0,
y≤1/3x+3,
y</span>≤ 5 - x

The vertices are the points of intersection between the constraints, or the outer bounds of the area that agrees with the constraints.
We know that x≥0 and y≥0, so there is one vertex at (0,0)
We find the other vertex on the y-axis, plug in 0 for x in the function:
y <span>≤ 1/3x+3
y </span><span>≤1/3(0)+3
y = 3. 
There is another vertex at (0,3)
Find where the 2 inequalities intersect by setting them equal to each other
(1/3x+3) = 5-x          Simplify Simplify Simplify
x = 3/2
Plugging in 3/2 into y = 5-x: 10/2 - 3/2 = 7/2
y=7/2
There is another vertex at (3/2, 7/2)
 
There is a final vertex where the line y=5-x crosses the x axis:
0 = 5 -x , x = 5
The final vertex is at point (5, 0)
Therefore, the vertices are:
(0,0), (0,3), (3/2, 7/2), (5, 0)
We want to maximize C = 6x - 4y.
Of all the vertices, we want the one with the largest x and smallest y. We might have to plug in a few to see which gives the greatest C value, but in this case, it's not necessary. 
The point (5,0) has the largest x value of all vertices and lowest y value.
Maximum of the function:
C = 6(5) - 4(0)
C = 30</span>
5 0
3 years ago
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