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slavikrds [6]
3 years ago
9

Explain how to solve a circle for y in order to completely graph the circle.

Mathematics
1 answer:
Lelechka [254]3 years ago
5 0
The formula to graph a circle is:
(x-h)^2+(y-v)^2=r^2

Step 1: find the center if the circle.
Using this equation: x^2+y^2=r^2
Step 2: calculate the radius by solving for r
Step 3: plot the radius on the coordinate plane
Step 4: connect the dots to the graph forming a round smooth circle

Step 5: replace your (h,v) with your center points and switch the signs in your equation for the formula of graphing a circle
Step 6: calculate the radius
Step 7: plot the radius points on the coordinate plane
Step 8: connect the dots to the graph of a circle
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Hope u can see this I will give 10 points to start of sorry for pushing u guys to type
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Right triangles. There is a 90 degree angle on both
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4 years ago
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Which of the following expressions are equivalent (equal) to 3(2x - 7)
velikii [3]

Answer:

6x - 21

Step-by-step explanation:

3(2x - 7)

Use the Distribute Property of Multiplication by multiplying the number outside the parenthesis with the numbers inside.

3 × 2x = 6x

3 × -7 = -21

Combine:

6x - 21

Hope this helped.

3 0
3 years ago
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The Pythagorean theorem is used to prove that a triangle is a(n) triangle.
sleet_krkn [62]
<span>The Pythagorean theorem is used to prove that a triangle is a(n) _________triangle. 

</span>The Pythagorean theorem is used to prove that a triangle is a right triangle. 
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We also have Pythagorean triangle. This is known as primitive right triangle.

The used of the said theorem is to prove that the square on the hypotenuse of a right triangle is equal to the sum of the squares on the two legs. One of the studies said that the theorem is talking about the area of the squares that are built on each side of the right triangle.


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4 0
3 years ago
How do you do this problem? Please explain.
horrorfan [7]

Answer:  8.632

<u>Step-by-step explanation:</u>

First, you need to find the length of AE. Since ΔAEC is a right triangle, we can use:

sin\ C=\dfrac{AE}{AC}\\\\\\sin\ 50 = \dfrac{AE}{5}\\\\\\5\ sin\ 50=AE\\\\3.83=AE

Next, Use Heron's formula to find the Area of ΔADE.

  • AE = 3.83
  • ED = 6
  • AD = 9

Heron's formula is:

A=\sqrt{s(s-a)(s-b)(s-c)}\quad \text{where}\ s = \dfrac{a+b+c}{2}\\\\s=\dfrac{AE+ED+AD}{2}=\dfrac{3.83+6+9}{2}=\dfrac{18.83}{2}=9.415\\\\A=\sqrt{9.415(9.415-3.83)(9.415-6)(9.415-9)}\\\\.\quad=\sqrt{9.415(5.585)(3.415)(0.415)}\\\\.\quad=\sqrt{74.519}\\\\.\quad=8.632

5 0
3 years ago
Simplify the problem thank you
NikAS [45]

Given the expression:

\displaystyle \large{ \sqrt[3]{ - 125} }

Definition:

\displaystyle \large{ y  = \begin{cases}   \pm \sqrt[n]{x}  \longrightarrow n  = (2,4,6,8,...)  \:  \: (x \geqslant 0) \\   \sqrt[n]{x}\longrightarrow n = (1,3,5,7,...) \:  \: (x \in \R) \end{cases}}

First, factor the -125. -125 comes from (-5)×(-5)×(-5) or (-5)^3.

\displaystyle \large{ \sqrt[3]{ ( - 5) \times ( - 5) \times ( - 5)} }

Because if (-5)^2 = 25 then 25×(-5) again will be -125.

Since this is the cube root, we have to pull out 3 terms in one. There are 3 fives that we can take off and therefore,

\displaystyle \large \boxed{ - 5}

5 0
3 years ago
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