All categories

4 years ago

How much should an eleven year old boy weigh?

Mathematics

1 answer:

Lera25 [3.4K]4 years ago

8 0

The average 11-year-old boy would be around 55 inches tall and weigh around 80 pounds.

You might be interested in

Find the percent using the percent equation. 238 cartons is what percent of 68 cartons?

LekaFEV [45]

Answer:350

Step-by-step explanation:

unknown is a

a% of 68=238

a/100 x 68=238

68a/100=238

Cross multiplying we get

68a=100x238

68a=23800

Divide both sides by 68

68a/68=23800/68

a=350

6 0

3 years ago

For what value of h makes this equation true? (Just checking my work)

Naddik [55]

I'm assuming that you meant h = 6 for choice B, in which case that would be correct.

7 0

3 years ago

Determine the area of the given region under the curve (1/x^4) [1,2]

Nikolay [14]

Answer:

$\displaystyle \frac{7}{24}$

General Formulas and Concepts:

Algebra I

Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

[Area] Limits of Riemann's Sums - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Step-by-step explanation:

Step 1: Define

$\displaystyle f(x) = \frac{1}{x^4} \\ \ [1, 2]$

Step 2: Find Area

[Integral] Set up area: $\displaystyle \int\limits^2_1 {\frac{1}{x^4}} \, dx$
[Integral] Rewrite: $\displaystyle \int\limits^2_1 {x^{-4}} \, dx$
[Integral] Reverse Power Rule: $\displaystyle \frac{-1}{3x^3} \bigg| \limits^2_1$
[Area] Fundamental Theorem of Calculus: $\displaystyle \frac{7}{24}$

Topic: Calculus

Unit: Basic Integration/Riemann Sums

Book: College Calculus 10e

6 0

3 years ago

Consider a population of size N = 100 with the three individual mutants with relative growth rate rA = 2, rB = 1.01, and rC = 0.

Salsk061 [2.6K]

Answer 1 / 25

Step-by-step explanation:

The probability that the first

of the three mutants will take over the population = 2 / 100

The probability that the second

of the three mutants will take over the population = 1.01 / 100

The probability that the third

of the three mutants will take over the population = 0.99 / 100

Therefore, the probability that each of the three mutants will take over the population = probability of the first,second or third = 2 / 100 + 1.01 / 100 + 0.99 / 100 = (2+1.01+0.99)/100 = 4 / 100 = 2/25

7 0

3 years ago

Explain two different ways to find the difference for 12-3?

bulgar [2K]

12 - 3 = 9
3 + 9 = 12
12 - 9 = 3

4 0

3 years ago