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solmaris [256]
3 years ago
6

Find the interquartile range for the data {5, 7, 9, 5, 6, 6, 6, 11, 11, 3, 3}

Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

4

Step-by-step explanation:

i dont really know how to explain i used an algebra calculator

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Mr. Rico's small business is starting to make a profit. His costs last week were -$352. His profit last week was $22. How many t
MrRa [10]

Answer:

The Answer is -16

Step-by-step explanation:

The equation to this would be -352 / 22, which would give you 16, hope this helped!

5 0
3 years ago
There are 100 people in a sport centre.
Arlecino [84]

We need to determinate who doesn't use anything, so first we must know the real number of who are practising: a person can do more things.

For doing this, is better use a three-circles graphic, but we try to do without it.

So

  • 16 pool + gym + track, and this number is sure
  • 38 gym + pool, but this number includes the people of 1st point. We must know who do only gym + pool: 38 - 16 = 22
  • 31 pool + track, this number also includes people of 1st point, so: only pool + track 31 - 16 = 15
  • 33 gym + track, this number also includes people of 1st point, so: only gym + track 33 - 16 = 17

now:

  • 67 gym, we must know who use only gym: 67 - 16 (gym + pool + track) - 22 (gym + pool) - 17 (gym + track) = 12
  • 62 pool, we must know who use only pool: 62 - 16 (gym + pool + track) - 22 (gym + pool) - 15 (pool + track) = 9
  • 56 track, we must know who use only track: 56 - 16 (gym + pool + track) - 15 (pool + track) - 17 (gym + track) = 8

now we must now who do some facility: let's sum all

16 + 22 + 15 + 17 + 12 + 9 + 8 = 99

99/100 practise something

So only 1/100 doesn't use nothing

The probability is 1%

7 0
3 years ago
1) Choose all of the common denominators of 2/3 and 7/9.
pishuonlain [190]

Common denominators of 9 and 3 are 9. 27

Common denominators of 9 and 2 are 18 36

8 0
3 years ago
PLEASE can someone explain why The exact value of sec ( π/6) is 2 /√ 3 ??
Umnica [9.8K]
\bf sec\left( \frac{\pi }{6} \right)\qquad recall\to sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus
\\\\
sec\left( \frac{\pi }{6}\right)\iff \cfrac{1}{cos\left( \frac{\pi }{6}\right)}
\\\\\\
\textit{check your Unit Circle for what the }cos\left( \frac{\pi }{6}\right)\ is
\\\\\\
\cfrac{1}{\frac{\sqrt{3}}{2}}\implies \cfrac{\frac{1}{1}}{\frac{\sqrt{3}}{2}}\implies 
\cfrac{1}{1}\cdot \cfrac{2}{\sqrt{3}}\implies \cfrac{2}{\sqrt{3}}
3 0
3 years ago
WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!! (image attatched)
alexgriva [62]
The answer would be the first one
4 0
4 years ago
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