This is complicated because I’m typing on a phone, but
24:30 simplified is 4:5
30:54 simplified is 5:9
10:5 simplified is 2:1
5:15 simplified is 1:3
32:72 simplified is 4:9
72:104 simplified is 9:13
56:7 simplified is 8:1
7:63 simplified is 1:9
Answer:
General Formulas and Concepts:
<u>Calculus</u>
- The derivative of a constant is equal to 0
Step-by-step explanation:
<u>Step 1: Define function</u>
y = 152 + 26 - 37
<u>Step 2: Simplify</u>
<em>Combine like terms</em>
y = 141
<u>Step 3: Find derivative</u>
<em>Derivative of any constant will be 0.</em>
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Solution,
Let P = ( x, -x + 6) = (x, 6 - x)
We want to solve this
( Distance from P to (0,0) )^2 = (Distance from P to (10, -10) )^2
x^2 + (6 - x)^2 = [ ( x - 10)^2 + ( 6 - x + 10)^2
x^2 + x^2 - 12x + 36 = x^2 - 20x + 100 + x^2 - 32x + 256 simplify
-12x + 36 = -52x + 356
40x = 320
x = 8
And y = -(8) + 6 = -2
So...P = ( 8, -2)
In mathematics, an equation is an equation that expresses two equations by joining them with an equal sign =. Equations in other languages and the word their relatives can have slightly different meanings; for example, in French, an equation is defined as containing one or more variables, but in English, it is an equal sign.
A well-formed expression consisting of two combined equations is an equation, and a variable makes the equation true. The variable for which the equation must be solved is also called the unknown, and the value of the unknown that satisfies the equation is called the solution of the equation. There are two types of equations: identities and constraint equations. The ID applies to all values of the variable. Constraint equations apply only to specific values of variables
Learn more about Equations here: brainly.com/question/2972832
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Answer:
(-2 , 2)
Step-by-step explanation:
A(-8 , 2) = (x1 , y1)
B(4 , -2) = (x2 , y2)
midpoint = (x1 + x2/2 , y1 + y2/2)
=(-8 + 4/2 , 2-(-2)/2)
=(-4/2 , 2+2/2)
(-2 , 2)
(3 , 7) = (x1 , y1)
(9 , 2) = (x2 , y2)
distance of PQ = 
=
=
=
=
=7.8 unit
Answer:
![xy^3 \sqrt[4]{y^3}](https://tex.z-dn.net/?f=xy%5E3%20%5Csqrt%5B4%5D%7By%5E3%7D)
Step-by-step explanation:
Recall the exponent property 
.
We can use this property to break the problem down:
![\sqrt[4]{x^4y^{15}}=\sqrt[4]{x\cdot x\cdot x\cdot x\cdot y^3\cdot y^3\cdot y^3\cdot y^3\cdot y^3}=\boxed{xy^3 \sqrt[4]{y^3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E4y%5E%7B15%7D%7D%3D%5Csqrt%5B4%5D%7Bx%5Ccdot%20x%5Ccdot%20x%5Ccdot%20x%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E3%7D%3D%5Cboxed%7Bxy%5E3%20%5Csqrt%5B4%5D%7By%5E3%7D%7D)
