Answer:
The length of rectangle is 6 units and the width is 1.5 units
Step-by-step explanation:
Let
L -----> the length of rectangle
W ----> the width of rectangle
we know that
The area of rectangle is equal to
we have
so
-----> equation A
A rectangle width is one fourth it’s length
so
----> equation B
substitute equation B in equation A and solve for L
take square root both sides
Find the value of W
Answer:
This is true. 9 is greater than 3.
To convert -34º C to Fahrenheit, plug the temperature in Celsius in the formula and solve.
F = 9/5C + 32
F = 9/5(-34) + 32
To solve this you must first multiply.
9/5 • -34 = -61.2
F = -61.2 + 32
Now add.
-61.2 + 32 = -29.2
The answer is -34º C equals -29.2º F.
Hope this helps!
(a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2+2ab+2b^2 =The answer
(a + b)^2 = a^2 + 2ab + b^2 => square of sums
(a - b)^2 = a^2 - 2ab + b^2 => square of deference
and of course one of most important ones:
a^2 - b^2 = (a - b)(a + b) => difference of squares
Best Answer: (a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2 + 2ab + 2b^2
a^4 + 4b^4 => i.e. 4a^2b^2 ,
a^4 + 4a^2b^2 + 4b^4 => a^2 + 2ab + b^2 = (a + b)^2, if : a = a^2 , b = 2b^2:
(a^2 + 2b^2)^2 = a^4 + 4a^2b^2 + 4b^4 => We can't add or subtract the value to the expression.
a^4 + 4a^2b^2 + 4b^4 - 4a^2b^2 =>
(a^2 + 2b^2)^2 - 4a^2b^2 =>
(a^2 + 2b^2 - 2ab)(a^2 + 2b^2 + 2ab) =>
(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)
Greetings!
