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vodka [1.7K]
3 years ago
15

Which is a perfect square? O 5 0001 O 36 44

Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

36 is answer

Step-by-step explanation:

Because 6x6=36 there is no sqaure of other

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Solve for W: P=2L + 2W<br><br>A. W=P-L<br>B. W= 1/2P - L<br>C. W= 1/2 P + L<br>D. W= 2P - L​
svetlana [45]

Answer:

B

Step-by-step explanation:

P=2L+2W

P-2L=2W (Subtract 2L from both sides of the equation)

2W=P-2L (Symmetric Property of Equality)

W=\frac{P-2L}{2} (Divide both sides of the equation by 2)

W=\frac{P}{2} -\frac{2L}{2} ("Split" the fractions)

W=\frac{1}{2}P-L (Simplify)

Hope this helps!

4 0
2 years ago
Tv originally cost $400 if the price of the TV increase by 15% what is the new price ​
Verizon [17]

Answer:

$460

Step-by-step explanation:

Thus, a product that normally costs $400 with a 15 percent discount will cost you $340.00, and you saved $60.00. You can also calculate how much you save by simply moving the period in 15.00 percent two spaces to the left, and then multiply the result by $400 as follows: $400 x .15 = $60.00 savings.

3 0
2 years ago
Help please !!!!! asap
AnnyKZ [126]
The answer: m∡BCD = 130° .
_____________________________________
Explanation:
______________________________
m∡BCD = 9x - 5 = our answer.
_____________________________
Note: (9x - 5) + (m∡C IN Δ  ACB)= 180 ;
____________________________
Reason: all angles on straight line add up to 180.
___________________________
Note: In Δ ACB; m∡A + m∡B + m∡c = 180.
_________________________________________
Reason: All three angles in any triangle add up to 180.
__________________________________________
Given  Δ ACB, we are given:
_____________
m∡C= ?
m∡B = (4x + 5)
m∡A = 65
_____________________
So, given  Δ ACB; m∡A + m∡B + m∡c = 180;
 →Plug in our known values and rewrite:
___________________________________
Given  Δ ACB; 65 + 4x + 5 + (m∡c) = 180;
  →Simplify, and rewrite:
___________________________________
Given  Δ ACB; 4x + 70 + (m∡c) = 180;
  →Subtract "70" from each side of the equation; and rewrite:
___________________________________
Given  Δ ACB; 4x + (m∡C) = 110;
   →Subtract "4x" from EACH SIDE of the equation; to isolate: "(m∡c)" on one side of the equation; and "solve in terms of "(m∡C)" ;
______________________________________________
Given Δ ACB' m∡C = 110 - 4x ;
__________________________________________
So, we know that: (110 - 4x) + (9x - 5) = 180; (since all angles on a straight line add up to 180.
____________________
We can solve for "x".
____________________
(110 - 4x) + (9x - 5) = 180;
________________________
Rewrite as: 
___________
(110 - 4x) + 1(9x - 5) = 180 ;  (Note: there is an implied coefficient of "1"; since anything multiplied by "1" equals that same value).
_______________________
Note the "distributive property of multiplication": 
_________________
 a*(b+c) = ab + ac ; AND:
 a*(b - c) = ab - ac .
_______________________
So, +1(9x - 5) = (+1*9x) - (+1*5) = 9x - 5 ;
__________________________
So we can rewrite:
___________________
(110 - 4x) + (9x - 5) = 180 ; as:
________________________
110 - 4x + 9x - 5 = 180 ;  We can simplify this by combining "like terms" on                                         the "left-hand side" of the equation:
_________________________________________________
110 - 5 = 105 ;
-4x + 9x = 5x; 
______________
So, rewrite as: 5x + 105 = 180;  Subtract "105" from EACH side; to get:
_____________________________________
 5x  = 75 ; Now, divide each side of the equation by "5"; 
              to get: x = 15.
_____________________________________________
Now, we want to know: m∡BCD; which equals:
_____________________________________________
 9x - 5 ;  let us substitute "15" for "x"; and solve:
______________________
9x - 5 = 9*(15) - 5 = 135 - 5 = 130.
_____________________________
The answer: m∡BCD = 130°
________________________
6 0
3 years ago
Amanda invests 5000 in a cd at an annual rate of 2%. What will her investment be worth at the end of three years?
Nookie1986 [14]
The equations would be 5000(1+0.02)^3 and the answer is $5306.04
3 0
3 years ago
Read 2 more answers
Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

7 0
3 years ago
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