2 years ago

Need help quick please. Find the area of the sector use 3.14 for pi

1 answer:

7 0

$\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=9\\ \theta =120 \end{cases}\implies \begin{array}{llll} A=\cfrac{(120)\pi (9)^2}{360}\implies A=27\pi \\\\\\ \stackrel{using~\pi =3.14}{A\approx 84.8} \end{array}$

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Bond [772]

Chebyshev came up with the limits on how much or how many of the data must lie close to the mean. In specific for any positive k, the proportion of the data that lies within k standard deviations of the mean is at least: 

1 - 1/k²

In this problem the mean is 47 yrs therefore:

(47 – 17.3) = 29.7 = (76.7 - 47)

The value of k is calculated using the formula:

29.7 / 11 = 2.7 = k

So the % of gym members aged between 19.4 and 76.6 is: 

1 - 1 / (2.6)² = 0.863 = 86.3 %

Therefore 86.3% of the gym members are aged between 19.4 and 76.6

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3 years ago

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IrinaVladis [17]

Answer:

Step-by-step explanation:

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3 years ago