How do I factor 25n^2 - 16?

Mathematics

1 answer:

wel2 years ago

8 0

Answer:

(5n + 4)(5n - 4)

Step-by-step explanation:

This is the difference of perfect squares. It follows a pattern of

(ax + b)(ax - b) where a is the square root of 25 and b is the square root of 16. The square root of 25 is 5, the square root of 16 is 4, so our factored quadratic is

(5n + 4)(5n - 4)

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4 0

2 years ago

Help me please, will give brainliest

ANTONII [103]

$A\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]$

$B\left[\begin{array}{ccc}3&-5&3\\2&3&1\\4&1&-3\end{array}\right]$

$Now,\\\\2B-A\\\\2\left[\begin{array}{ccc}3&-5&3\\2&3&1\\4&1&-3\end{array}\right]-\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]\\\\=\left[\begin{array}{ccc}6&-10&6\\4&6&2\\8&2&-6\end{array}\right] -\left[\begin{array}{ccc}1&0&5\\0&-5&7\\0&3&-4\end{array}\right]\\\\=\left[\begin{array}{ccc}5&-10&1\\4&11&-5\\8&-1&-2\end{array}\right]$