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1 year ago

Work out the equation of the line which has a gradient of -2 and passes through the point (4, 8).

Mathematics

2 answers:

konstantin123 [22]1 year ago

7 0

Answer:

y = -2x + 8

Step-by-step explanation:

Formula = y = mx+c

where m = gradient of the line

and c= y intercept

in the coordinate (4,8), the point where the line intercepts the y axis is 8

this substitute:

y= mx + 8

Gradient = m = -2

Therefore, equation of line= y= -2x +8

Please mark as Brainliest and best of luck on your homework.

max2010maxim [7]1 year ago

3 0

Answer:

y = -2x + 16.

Step-by-step explanation:

We are given the slope and a point on the line, so

we use the point-slope form of a straight line:

y - y1 = m(x - x1)

Here gradient m = -2, x1 = 4 and y1 = 8 , so we have:

y - 8 = -2(x - 4)

y - 8 = -2x + 8

y = -2x + 16.

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3 years ago

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Which equation represents the same line as the points in the table

vodomira [7]

Answer:

$y=\frac{-3}{4} x+2$

Step-by-step explanation:

First, we can find the slope using the slope equation and two of the points.

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Now that we have the slope, all we need is the y-intercept. Luckily, it gives it to us in the table. The x value of y-intercepts will always be 0. Looking at the table, we see that the point where x=0 is (0,2). Thus, the y-intercept is 2. Your final equation is

$y=\frac{-3}{4} x+2$

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3 years ago

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PLS HELP I NEED AN ANSWER ASAP

guajiro [1.7K]

Answer:

4/sin (35)

Step-by-step explanation:

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3 years ago