Question

Work out the equation of the line which has a gradient of -2 and passes through the point (4, 8).​

Answer 1

Answer:

y = -2x + 8

Step-by-step explanation:

Formula = y = mx+c

where m = gradient of the line

and c= y intercept

in the coordinate (4,8), the point where the line intercepts the y axis is 8

this substitute:

y= mx + 8

Gradient = m = -2

Therefore, equation of line= y= -2x +8

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Answer 2

Answer:

y = -2x + 16.

Step-by-step explanation:

We are given the slope and a point on the line, so

we use the point-slope form of a straight line:

y - y1 = m(x - x1)

Here gradient m = -2, x1 = 4 and y1 = 8 , so we have:

y - 8 = -2(x - 4)

y - 8 = -2x + 8

y = -2x + 16.