Work out the equation of the line which has a gradient of -2 and passes through the point (4, 8).
2 answers:
Answer:
y = -2x + 8
Step-by-step explanation:
Formula = y = mx+c
where m = gradient of the line
and c= y intercept
in the coordinate (4,8), the point where the line intercepts the y axis is 8
this substitute:
y= mx + 8
Gradient = m = -2
Therefore, equation of line= y= -2x +8
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Answer:
y = -2x + 16.
Step-by-step explanation:
We are given the slope and a point on the line, so
we use the point-slope form of a straight line:
y - y1 = m(x - x1)
Here gradient m = -2, x1 = 4 and y1 = 8 , so we have:
y - 8 = -2(x - 4)
y - 8 = -2x + 8
y = -2x + 16.
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