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STALIN [3.7K]
3 years ago
5

Questions 3-5 please and thank you

Mathematics
1 answer:
vekshin13 years ago
7 0

Answer:

too far away and too blurry cant see it

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Marcus wants to use a model to determine the difference
grigory [225]

Electron transfer theory describes the parameters which control the rate at which an electron is transferred from one atom or molecule to another.

<h3>What was the basic principle of Marcus theory?</h3>
  • In theoretical chemistry, Marcus theory is a theory originally developed by Rudolph A. Marcus, starting in 1956, to explain the rates of electron transfer reactions – the rate at which an electron can move or jump from one chemical species.
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  • Marcus Hush theory (M-H theory) was developed in 1956 by Rudolph A. Marcus which explains the fundamentals of the redox/ electron transfer reactions in terms of the rate of jumping/moving an electron from oxidant species (electron donor) to the reductant (electron acceptor).
  • The "Marcus Inverted Region" (MIR) is that part of the function of rate constant versus free energy where a chemical reaction becomes slower as it becomes more exothermic.

We want to see how we can model the difference: -8 - 3 + 3

The correct option is D:

"add 3 positive counters and 3 negative counters"

We know that Marcus starts with 8 negative counters, corresponding to the first term in our difference.

Now, let's study the math of our expression.

-8 - 3 + 3

Remember that we can perform the operation in any order we want, so we can write this as:

-8 + (-3 + 3)

Notice that the thing inside the parentheses is equal to zero, so we have:

- 8 + (-3 + 3) = -8

So to not change the value, we add 3 and we subtract 3.

Now if we have 8 negative counters, and we want to add 3 positive counters and not change the value, then we also need to add 3 negative counters to "cancel" the 3 positive counters we added.

Then the correct option is D.

To learn more about Marcus refer to,

brainly.com/question/23140234

#SPJ1

8 0
1 year ago
A projectile is launched at a height of h feet above the ground at an angle of θ with the horizontal. The initial velocity is v0
Nataliya [291]

Answer:

Simple

Step-by-step explanation:

You Quit The Class

8 0
3 years ago
Least common multiple of 8 40 and 64??
dem82 [27]

Answer: 320

Step-by-step explanation:

7 0
4 years ago
Which equation has x = -i and x = = 21v3 as two of its solutions?
Drupady [299]

Answer:

The equation in option A is correct.

Step-by-step explanation:

Given the equation

\:y=x^4+13x^2+12

Let us find the solution by setting y=0

x^4+13x^2+12=0\:\:\:\:\:

\mathrm{Rewrite\:the\:equation\:with\:}u=x^2\mathrm{\:and\:}u^2=x^4

u^2+13u+12=0

if ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

u+1=0\quad \mathrm{or}\quad \:u+12=0

u=-1,\:u=-12

\mathrm{Substitute\:back}\:u=x^2,\:\mathrm{solve\:for}\:x

x^2=-1,\:x^2=-12

solving

x^2=-1

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{-1},\:x=-\sqrt{-1}

x=i,\:x=-i            ∵ \:\sqrt{-1}=i

solving

x^2=-12

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{-12},\:x=-\sqrt{-12}

x=2\sqrt{3}i,\:x=-2\sqrt{3}i

Hence, the solutions are:

x=i,\:x=-i,\:x=2\sqrt{3}i,\:x=-2\sqrt{3}i

Therefore, the equation in option A is correct.

6 0
3 years ago
Please help me with this. I'll mark brainiest
atroni [7]

Answer:

Option 3 (C)

Step-by-step explanation:

Given the scores of the students: 3, 4, 4, 5, 5, 6, 8, 10, 10, 12, 15, 18

To find the box plot that represents the data set, we need to find:

Min, Q1, median, Q3, and Max, which are all represented on a box plot.

Min = 3

Max = 18

Median = the average of the 6th and 7th data value = (6+8)/2 = 14/2 = 7

Q1 = the average of the 3rd and 4th data values = (4+5)/2 = 4.5

Q3 = the average of the 9th and 10th data values = (10+12)/2 = 11

The box plot that closely represented all these values is the box plot in option 3.

8 0
3 years ago
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