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Rufina [12.5K]
2 years ago
15

Does anyone know the answer? Please and Thank you! Algebra

Mathematics
1 answer:
Over [174]2 years ago
3 0

Answer:

Step-by-step explanation:

y = mx + b

we can see the slope is down hill,  so it's  negative

when the X is zero then it's 2

b = 2

slope is rise over run  2/3

y = -2/3x + 2

the slope is -2/3  (note the negative)

the y intercept is 2  

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8_murik_8 [283]
-5,424.3 ...............
7 0
3 years ago
Find k if (x+1) 2x^3+kx^2+1
Viktor [21]
<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

k = 1

<h2>Step-by-step explanation:</h2>

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

<em>This is because;</em>

i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.

ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

=> (-3)² - 9

=> (9) - 9 = 0

Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

2(-1) + k(1) + 1 = 0

-2 + k + 1 = 0

k - 1 = 0

k = 1

Therefore the value of k is 1.

3 0
2 years ago
LK is tangent to circle J at point K. Circle J is shown. Line segment J K is a radius. Line segment K L is a tangent that inters
Evgen [1.6K]

Answer:

(B)r=\dfrac{85}{12}

Step-by-step explanation:

Given a circle centre J

Let the radius of the circle =r

LK is tangent to circle J at point K

From the diagram attached

  • LX=6
  • Radius, XJ=JK=r
  • LK=11

Theorem: The angle between a tangent and a radius is 90 degrees.

By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.

Using Pythagoras Theorem:

(6+r)^2=r^2+11^2\\(6+r)(6+r)=r^2+121\\36+6r+6r+r^2=r^2+121\\12r=121-36\\12r=85\\r=\dfrac{85}{12}

The length of the radius, r=\dfrac{85}{12}

8 0
3 years ago
Read 2 more answers
HELP ASAP PLZ HELP<br> I will give a brain list if it is right !!! <br> just help me plz
lilavasa [31]
Answer: A

Explanation:
First you have to write the model in an equation form.

6x+5=15

Subtract 5 from both sides

6x=10

Divide 6 from both sides

X=10/6

Simplify

X=5/3 or 1.67
8 0
3 years ago
Read 2 more answers
I need help with this because I'm not very good at understanding this.
HACTEHA [7]

Answer:

the initial value is 2

Step-by-step explanation:

"y=mx+b" is the equation

"b" is the initial value, and there is no "b" value

4 0
3 years ago
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