Answer:
All points on line x+y = 0 or x-y=0 will satisfy the transformation.
Step-by-step explanation:
Let (x, y) be the general such point.
Hence rotating it by 180 deg. counterclockwise will give us (-y,-x).
Reflecting (-y,-x) on x axis gives us (-y,x).
Hence if (x,y) = (-y,x) then all ( x, y) where x = -y or x+y = 0 or x=y or x-y=0 will satisfy this condition.
All points on line x+y = 0 or x-y=0 will satisfy the transformation.
The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as
v+ = 2.29 1mile/hour
<h3>What is the rate Evelyn and
Meredith were paddling?</h3>
Generally, the equation for the up and downstream motion is mathematically given as
vup=v-2
vdown=v+2
Therefore, Statement interpretation
2/3=40*1/60
3+2/3hr=11/3
Where, tup+tdown=11/3
tup+tdown=11/3
1/Vup+1/vdown=11/3
Considering the LCD equation
3(v-2)(V+2)
Hence
11v^2-6v-44=0
Resolving using the equation we have
v+ = 2.29 1mile/hour
v- = -1.745 mile hour
Read more about Speed
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Answer:
Tyler is correct. The temperature dropped at a rate of about 4° per hour between 4 and 6, while the temperature dropped at about 2.25° per hour between 6 and 10.
Edit: Explanation
The question is asking about which window of time had a <em>faster</em> decline in temperature, not a larger total change in temperature.
In a 2 hour timeframe, the temperature dropped 8°. (4-6 PM)
In a separate 4 hour timeframe, the temperature dropped 9°. (6-10 PM)
To find which window had a faster change in temp, I took the total temperature drop for each timeframe, then divided it by the number of hours each drop took.
8° / 2 = 4° per hour for 4-6 PM
9° / 4 = 2.25° per hour from 6-10 PM
Since the speed at which the temperature dropped per hour was greater from 4-6 PM than 6-10 PM, Tyler was correct.
5h - w = 170
for h = 77
w = 5h - 170
w = 5*77 - 170
w = 385 - 170
<span>w = 215
Shoutout to @himanshuchaturvedi
Your answer is : w = 215
Have an amazing day and stay hopeful!
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