Queston 4: The range of the relation is : (-2,4)
Question 5: the domain of the relation is:
{2, 2.1, 5.1, 5.5, 6}
Question 6: The relation is not a function because it two of the x value have the same y values. Therefore it is not a function as it does not pass the vertical line test.
(-4, 0) and (-3, 0) both have 0 for the y coordinate. A function can’t have this.
You do -2 plus 4. Answer is 2.
Then do 2-(-2) which is 0.
The final answer is 2.
Answer:
10x-1y
hope this helps
have a good day :)
Step-by-step explanation:
I am not sure, but the answer is probably option A. Graph A.
Answers:
x = 4
EF = 14
CF = 7
EC = 7
-------------------------------------------------------------
-------------------------------------------------------------
Work Shown:
C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent.
Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4
Now that we know that x = 4, we can use this to find EC and CF
Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7
Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7
As expected, EC = CF (both are 7 units long).
By the segment addition postulate, we can say EC+CF = EF
EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
