WILL GIVE BRAINLIEST! What’s the perimeter and area of this figure?

Please Help!!!!!! You have twice as many nickels as pennies. you have $1.10. how many of each coin do you have? Solve each probl

astraxan [27]

There are 20 nickels and 10 pennies.

20 cents x 5 is $1.00 and 10 cents x 1 is 10 cents so it is $1.10 because a nickel is 5 cents so 20x5 is a dollar and a penny is worth 1 cent and 10 pennies is 10 cents so $1.00+$0.10=$1.10 brainliest is appreciated! :)

4 0

3 years ago

Really need need help on this please

Alexxx [7]

Answer:

$\frac{7}{2}$

Step-by-step explanation:

$\frac{12-3y}{2} + y (\frac{2y-4}{y})$

we substitute the value of "y" in the equation:

$\frac{12-3(3)}{2} + 3 (\frac{2(3)-4}{3})\\\\\frac{12-9}{2} + 3 (\frac{6-4}{3})\\\\\frac{3}{2} + 3 (\frac{2}{3})\\\\\frac{3}{2} + 2\\\\\frac{7}{2}$

3 0

3 years ago

Help me please. 20+(-16)4

Sphinxa [80]

P.E.M.D.A.S
First , you multiply.

200+(-16)4
200+(-64)

Since they have different signs, you subtract and keep the sign of the greater absolute value.

200+(-64)=136

8 0

3 years ago

Which of the following expressions is equal to -3X2-27?

ale4655 [162]

Answer: B

Step-by-step explanation:

-3x^2-9xi+9ix-27

-3x^2-27

8 0

3 years ago

Find x so that the points (x,x+1), (x+2,x+3) and (x+3,2x+4) form a right-angled triangle.

azamat

Let a, b, and c be vectors each starting at the origin and terminating at the points (x, x + 1), (x + 2, x + 3), and (x + 3, 2x + 4), respectively.

Then the vectors a - b, a - c, and b - c are vectors that point in directions parallel to each of the legs formed by the triangle with these points as its vertices.

If this triangle is to contain a right angle, then exactly one of these pairs of vectors must be orthogonal. In other words, one of the following must be true:

(a - b) • (a - c) = 0

or

(a - b) • (b - c) = 0

or

(a - c) • (b - c) = 0

We have

a - b = (x, x + 1) - (x + 2, x + 3) = (-2, -2)

a - c = (x, x + 1) - (x + 3, 2x + 4) = (-3, -x - 3)

b - c = (x + 2, x + 3) - (x + 3, 2x + 4) = (-1, -x - 1)

Case 1: If (a - b) • (a - c) = 0, then

(-2, -2) • (-3, -x - 3) = (-2)×(-3) + (-2)×(-x - 3) = 2x + 12 = 0 ==> x = -6

which would make a - c = (-3, 3) and b - c = (-1, 5), and their dot product is not zero. Then the triangles vertices are at the points (-6, -5), (-4, -3), and (-3, -8).

Case 2: If (a - b) • (b - c) = 0, then

(-2, -2) • (-1, -x - 1) = (-2)×(-1) + (-2)×(-x - 1) = 2x + 4 = 0 ==> x = -2

which would make a - c = (-3, -1) and b = (-1, 1), and their dot product is also not zero. The vertices are the points (-2, -1), (0, 1), and (1, 0).

Case 3: If (a - c) • (b - c) = 0, then

(-3, -x - 3) • (-1, -x - 1) = (-3)×(-1) + (-x - 3)×(-x - 1) = x ² + 4x + 6 = 0

but the solutions to x here are non-real, so we throw out this case.

So there are two possible values of x that make a right triangle, x = -6 and x = -2.

3 0

3 years ago