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katrin [286]
3 years ago
5

Consider the equation showing the distributive property.

Mathematics
1 answer:
Tpy6a [65]3 years ago
5 0

Answer:

D = 31

Step-by-step explanation:

Consider the equation showing the distributive property.

84 +93 = 3 (28+ D)

The unknown value we are asked to find is D

Hence:

84 + 93 = 84 + 3D

Collect like terms

84 - 84 + 93 = 3D

93 = 3D

D = 93/3

D = 31

Therefore, the unknown value that would make the equation true is 31

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Answer:

Presumably the first graph solely based on its shape.

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3 years ago
Josiah want to gp to the movies with his friends. Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purcha
ss7ja [257]

Answer:

The equation that represents the number of tickets that Josiah can buy with $45.50

3 + 8.50x = 45.50

The number of number of tickets that Josiah can buy with $45.50 is 5 ticketa

Step-by-step explanation:

Let the number of tickets be represented by x

Tickets are $8.50 plus he must play Fangalingo a $3 transaction fee for purchasing the tickets online.

The equation that represents the number of tickets that Josiah can buy with $45.50

$3 + $8.50 × x = $45.50

3 + 8.50x = 45.50

Solving further for x

3 + 8.50x = 45.50

8.50x = 45.50 - 3

8.50x = 42.50

x = 42.50/8.50

x = 5

Hence, the number of number of tickets that Josiah can buy with $45.50 is 5 ticketa

3 0
3 years ago
Can you please show the working?
creativ13 [48]

The Price of Car A rounded to the Nearest £100 is £12400

The Price of Car B rounded to the Nearest £100 is £16800

The Price of Car C rounded to the Nearest £100 is £14600

Difference between the Rounded Price and Original Price of Car A :

⇒ (£12400 - £12380) = £20

Difference between the Rounded Price and Original Price of Car B :

⇒ (£16800 - £16760) = £40

Difference between the Rounded Price and Original Price of Car C :

⇒ (£14600 - £14580) = £20

From the above, We can Notice that :

The Price of Car B changes by the greatest amount.

4 0
3 years ago
Solve for the variable: x + 9 > -4
Marina CMI [18]
Hi \\  \\ x+9\ \textgreater \ -4 \\  \\ x\ \textgreater \ -4-9 \\  \\ \boxed{x\ \textgreater \ -13} \\  \\ S=\{x\in~\mathbb{R} |x\ \textgreater \ -13\} \\  \\  \\
3 0
3 years ago
Read 2 more answers
Find the GCF for -10c^2d and 15cd^2
sveta [45]
-10c^2d and 15cd^2
GCF
5cd
8 0
3 years ago
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