Question

Find the perimeter of the following shape, rounded to the nearest tenth: coordinate plane with quadrilateral ABCD at A 0 comma 0, B 5 comma negative 1, C 3 comma negative 5, and D negative 2 comma negative 4 19.1 20.39 22.8 24.4

Answer 1

The perimeter of a figure is the sum of the lengths of the sides used to make the given figure. The perimeter of the shape ABCD is 19.1(5.099+4.4721+5.099+4.4721).

What is the perimeter?

The perimeter of a figure is the sum of the lengths of the sides used to make the given figure.

The perimeter of the shape can be found by finding the length of the different sides, therefore,

$AB = \sqrt{(5-0)^2+(-1-0)^2} = \sqrt{26} = 5.099$

$BC = \sqrt{(3-5)^2+(-5+1)^2} = \sqrt{20} = 4.4721$

$CD = \sqrt{(-2-3)^2+(-4+5)^2} = \sqrt{26} = 5.099$

$AD=\sqrt{(-2-0)^2+(-4-0)}=\sqrt{20} = 4.4721$

Hence, the perimeter of the shape ABCD is 19.1(5.099+4.4721+5.099+4.4721).

Learn more about perimeter here:

brainly.com/question/10466285

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