Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:
Hence the bounds of the interval are found as follows:
The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
So first simplify 11/6x into 11x/6. Then -13/10x into -13x/10. So you should now have (-13x/10-11x/4)-3/2. Combine the like terms -13x/10 and -11x/4 to get -81x/20 and then with your left over -3/2= -81x/20-3/2
Answer:
(y - 2)²
Step-by-step explanation:
9y² - 12y + 4 ← is a perfect square of the form
(ax - b)² = a²x² - 2abx + b²
Compare like terms with 9y² - 12y + 4, thus
a² = 9 ⇒ a = 3
b² = 4 ⇒ b = 2 and
- 2ab = - 2 × 3 × 2 = - 12
Thus
9y² - 12y + 4 = (3y - 2)²
Answer:
h < 2
Step-by-step explanation:
Step 1: Distribute
10h + 40 < 60
Step 2: Subtract 40 on both sides
10h < 20
Step 3: Divide both sides by 10
h < 2
The answer would be 78. C
