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3 years ago

Can someone correct me I don't know if I got it right

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

8 0

Answer:

yup

Step-by-step explanation:

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Help quick please!!

Korolek [52]

Answer:

Difference of squares:

y^4−25

16x^2−81

Not difference of squares:

20m^2n^2−121

p^8−q^5

Step-by-step explanation:

y^4−25

(y²)² - 5²

16x^2−81

(4x)² - 9²

20m^2n^2−121

20 is not a perfect square

p^8−q^5

q⁵ is not a perfect square

3 0

3 years ago

Xoxoxoxozooxoxoxoxoo

densk [106]

Ummm what? I don’t get it

7 0

3 years ago

Need help ASAP !!!!!!!

Anestetic [448]

First we distribute $\frac{1}{5}$ into $n$ and $-\frac{1}{7}$ .

$\frac{1}{5} * n = \frac{1}{5} n$
$\frac{1}{5} * -\frac{1}{7} = - \frac{1}{35}$

That makes the left side of the equation

$\frac{1}{5} n - \frac{1}{35} = \frac{1}{6} n$

Now we subtract $\frac{1}{5}n$ from $\frac{1}{6} n$ , which makes $\frac{1}{30}$

Now the equation is

$-\frac{1}{35} = -\frac{1}{30n}$

Our goal is to isolate $n$ , so we both sides by 30

$30* -\frac{1}{35} = - \frac{1}{30}n * 30$

That will make the equation

$- \frac{30}{35} = -n$

We multiply -1 on both sides of the equation:

$\frac{30}{35} = n$

Finally we simplify $\frac{30}{35}$ , which makes $\frac{6}{7}$

So the answer is $n = \frac{6}{7}$

5 0

3 years ago

Solve for the variable: 12 = 5x = 7

IrinaVladis [17]

Hello from MrBillDoesMath!

Answer: x = 1

Discussion :

Per the author, the equation to solve is 12 = 5x + 7

Isolate the "x" variable by subtracting 7 from both sides of the equation:

12 = 5x + 7

-7 = -7

---------------------

12-7 = 5x + 0

5 = 5x

Dividing both sides by 5 gives x - 1

Regards, MrB

6 0

3 years ago

WORTH 25 POINT PLEASE HELP WILL MARK THE BRAINLIST

AleksandrR [38]

Answer:

sure

Step-by-step explanation:

what is the question

4 0

3 years ago