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Bingel [31]
3 years ago
13

Can someone correct me I don't know if I got it right

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

yup

Step-by-step explanation:

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Please help me with this! ASAP
kobusy [5.1K]

The question gives you 4 different numbers that could be x, so you have to replace each x in each problem and solve. If the two answers are equivalent, that is your answer. For the first one, 6 times 2 is 12, minus 2 is 10. 5 times 2 is 10, plus 3 is 13. 10 is not equal to 13, so that is not the answer. For 5, 6 times 5 is 30, minus 2 is 28. 5 times 5 is 25, plus 3 is 28, so therefore the answer is x=5

4 0
3 years ago
What is the correct answer for this problem?Explain
bearhunter [10]
To solve this you would make a triangle, Assuming you had a piece of paper.

It would look like the picture included (where ever that is) sorry for the horrible drawing with mouse.

You can then you Pythagorean Theorem to solve this

a^{2} + b^2 =c^2

width will be (a) 

put in your variables

a^2 + 72^2 = 90^2
a^2 + 5184 = 8100

Subtract 5184 over and get 
a^2 = 2916

square root both sides and get 
a=54

the field is 54 meters wide
  

8 0
3 years ago
Read 2 more answers
Solve the equation.<br> -5r-1=7r+5
Ksivusya [100]

Answer:

-1/2

Step-by-step explanation:

3 0
3 years ago
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Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized.
Maksim231197 [3]

Answer:

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8 0
3 years ago
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What two consecutive integers have a sum of 75?
marshall27 [118]

Answer:

37 and 38.

Step-by-step explanation:

Let the smaller integer be x.

Thus, the larger integer is (x+1) since it is consecutive.

x+(x+1)=75

2x+1=75

Subtract both sides by 1:

2x+1-1=75-1

2x=74

Divide both sides by 2:

\frac{2x}{2}=\frac{74}{2}

x=37

To find the other number, simply add 1 to 37 to get 38.

7 0
3 years ago
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