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loris [4]
2 years ago
14

SOMEONE HELP ME PLEASE IM STUCK ON THIS

Mathematics
1 answer:
noname [10]2 years ago
4 0

Step-by-step explanation:

2×2×2×2

3 3 3 3

2×2×2×2

3×3×3×3

16

3×3×3×3 (divide)

= 16/81

hope it helpsss!!

can you mark me as the brainliest

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it's a week before the maths festival a maths exhibition costa £75.40 and so far 12 have been bought. what's the total income so
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£75.40*12= £904.80


A quick multiplication
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Given f(x) = 10-4x<br>find f (8)<br>​
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One container of Tums® costs 4.00 dollars. Each container has eighty 1.00 g tablets. Assume each Tums® is 40.0 percent CaCO₃ by
Anna007 [38]

Answer:

The total cost is 1.25 dollars.

Step-by-step explanation:      

The reaction between HCl and CaCO₃ is giving by:

2HCl(aq) + CaCO₃(s)   →   CaCl₂(aq) + CO₂(g) + H₂O(l) (1)

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According to equation (1), 2 moles of HCl react with 1 mol of CaCO₃, so to neutralize HCl, we need the next amount of CaCO₃:

m CaCO_{3} = (\frac{1 \cdot mol HCl}{2}) \cdot M_{CaCO_{3}} = (\frac{0.500L \cdot 0.400 \frac {mol}{L}}{2}) \cdot 100.01 \frac{g}{mol} = 10.001 g      

The CaCO₃ mass of each tablet is:

m CaCO_{3} = 1 g_{tablet} \cdot \frac{40g CaCO_{3}}{100g_{tablet}} = 0.4g

Hence, the number of tablets that we need to neutralize the HCl is:

number_{tablets} = ( \frac{1 tablet}{0.4 g CaCO_{3}}) \cdot 10.001g CaCO_{3} = 25  

Finally, if every 80 tablets costs 4.00 dollars, 25 tablets will cost:

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<u>So, the total cost to neutralize the HCl is 1.25 dollars.</u>

I hope it helps you!

7 0
3 years ago
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got this from someone who answered this for me 
5 0
4 years ago
How do u solve this?
Stella [2.4K]
The answer would be 1287
8 0
3 years ago
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