We can find a formula for nth term of the given sequence as follows:
1, 5, 12, 22, 35
The 1st differences between terms:
4, 7, 10, 13
The 2nd differences :
3, 3, 3
Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form:
, where c is a constant. The coefficients a, b, and the constant c can be found.
We can form the following 3 equations with 3 unknowns a, b, c:

Solving for a, b, c, we get:
a = 3/2, b = -1/2, c = 0
Therefore, the nth term of the given sequence is:

Answer:
Step-by-step explanation: infinitely many solutions (please give brainliest)
9514 1404 393
Answer:
Step-by-step explanation:
It can be helpful to actually see the graph. For 0 ≤ θ ≤ π, a circle is developed above the x-axis, symmetrical about the y-axis (θ=π/2). For π ≤ θ ≤ 2π, the same circle is traced again in the same direction (CCW), as values of r are negative for those angles.
The circle has a radius of 2.5, centered at (0, 2.5), so the diameter is 5 units. The length of the diameter is the farthest distance between any two points on a circle.
The <em>correct answers</em> are:
C) No: we would need to know if the vertex is a minimum or a maximum; and
C)( 0.25, 5.875).
Explanation:
The domain of any quadratic function is all real numbers.
The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.
If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.
There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.
The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).
Answer:
{-8,28}
Step-by-step explanation:
|10-x|=18
The absolute value has two solutions, one positive and one negative.
10-x = 18 and 10-x = -18
Subtract 10 from each side
10-10-x = 18-10 10-10-x=-18-10
-x = 8 -x = -28
Multiply each side by -1
x = -8 x = 28