Answer:
30 = 5y - 4x or 6 + (4x/5) = y (in mx + c = y form)
Step-by-step explanation:
slope =
- 
/ 
- 
now, = 2
= -5
insert the values of these two in the slope formula and equate it with 4/5.
by cross multiplication, obtain equation.
the equation is 30 = 5y-4x.
hope this helps you!
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer:
(1,7)
Step-by-step explanation:
first find the slope
9-5/4-(-2)=4/6=2/3
5+2=7
-2+3=1
=(1,7)
Answer:
Advertising and promotion.
Borrowing costs.
Employee expenses.
Equipment and supplies.
Insurance, license, and permit fees.
Research expenses.
Technological expenses.
Step-by-step explanation:
Answer:
Area of Shaded Region 
Area of Semicircle
Step-by-step explanation:
Area of Shaded Region = Area of Sector - Area of Semicircle
<u>Area of Sector</u>
Radius of the sector =20cm
<u>Area of Semicircle</u>
Since AB is the diameter of the semicircle
Radius of the Semicircle=20/2=10cm
Area of semicircle
Therefore, area of Shaded Region
Area of Square =20 X 20 
