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7nadin3 [17]
2 years ago
6

Peter drove 1.5 hours at an average speed of 40 mph. He then drove for another 40km.

Mathematics
1 answer:
egoroff_w [7]2 years ago
5 0

Answer:

john drove for 3 hours at a rate of 50 miles per hour and for 2 hours at 60 miles per hour. 

Step-by-step explanation:

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69 points!!!
Amiraneli [1.4K]

Answer:

C)  The solution for the given system of equations are A(0,-5) and B(-4,3)

Step-by-step explanation:

The given system of equation are : x^{2}  + y^{2}  = 25\\2x  + y  = -5

from equation 2, we get   y = -5 - 2x .

Put the above value of y in the equation (1).

We get: x^{2}  + y^{2}  = 25  \implies x^{2}  + (-5-2x)^{2}  = 25

By ALGEBRAIC IDENTITY:

(a+b)^{2}   = a^{2}  +  b^{2}  + 2ab\\ (-5-2x)^{2} = (-5)^{2}  +  (-2x)^{2}  + 2(-5)(-2x)

or, x^{2}  + (-5-2x)^{2}  = 25  \implies x^{2} + (25  +  4x^{2}  + 20x)  = 25

or, 5x^{2}  + 20x = 0  \implies x(5x + 20) = 0

⇒ x = 0 or,   x  = -20/5 = -4

So, the possible values for x are: x  = 0 or  x  = -4

If x  = 0, y = -5-2x = -5-2(0) = -5

and if x = -4, y = -5 -2(-4)   = -5 + 8  = 3

Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)

8 0
3 years ago
Carol bought a coloring book. It is 11 inches long and 8 inches wide. What is the diagonal length of the book?
Leokris [45]

Answer:

13.6 inches

Step-by-step explanation:

We can use Pythagorean theorem: c=\sqrt{a^{2} +b^{2} }

Let c be the diagonal length, a for length, and b for width.

Substitute the values.

c=\sqrt{11^{2}+8^{2}  }

c=13.6 inches

7 0
3 years ago
Rewrite 3/35 and 1/10 so they have common denominators
Aleks [24]

Answer:

\frac{6}{70} and \frac{7}{70}

Step-by-step explanation:

The LCM of 35 and 10 is 70.

35×2=70

10×7=70

You got to multiply 3 with 2 and 1 with 7 to make 6/70 and 7/70.

5 0
3 years ago
Solve for the difference <br><br><br><br><br><br> `7.2-3.67`
storchak [24]
The correct answer is 3.53
7 0
2 years ago
Find x. Round to the nearest degree.
jeka94

The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.


We want angle x, which is opposite the side of length 39.


Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x


or 1521 = 3481 + 1296 - 2(36)(59) cos x


Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x

-3256 = -4248cos x

-3256

Then: cosx = --------------- = 0.766

-4248


Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)

5 0
3 years ago
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