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Vesnalui [34]
3 years ago
11

Swifty Corporation started the year with total assets of $300000 and total liabilities of $240000. During the year the business

recorded $633000 in revenues, $335000 in expenses, and dividends of $61000. Stockholders’ equity at the end of the year was
a) 275000
b) 363000
c) 305000
d) 297000
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer:

The answer is d) 297000

Step-by-step explanation:

The stockholders' equity of a company represents the amount of money that will be returned to the accionists if all the assests will be liquidated and the compan'y debt will be paid.  So to calculate the Swifty Corporation stockholders' equity at the end of the year you need to add all what enters to the company (assets and revenues) and substract all what goes out (liabilities, expenses and dividends).

- What enters?

  • The starting assets = $300.000
  • Revenues = $633.000

Total incomes = $300.000 + $633.000 = $933.000

- What goes out?

  • Liabilities = $240.000
  • Expenses = $335.000
  • Dividends = $ 61.000

Total expenses = $240.000 + $335.000 + $61.000 = $636.000

Stockholders' equity = Total income - Total expenses

Stockholders' equity = $933.000 - $636.000 = $297.000

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aniked [119]

Answer:

88

A:J

8:3

a - 40 = j

8y - 40 = 3y

5y = 40

y = 8

8 *11 = 88

Step-by-step explanation:

Hope i helped!  have a nice day

5 0
3 years ago
Read 2 more answers
Shelly is 3 years older than Michele. Four years ago the sum of their age was 67. Find the age of each person.
lawyer [7]

total of ages now is 67 + 4 + 4 = 75

S=shelly

M= Michelle

Michelle is 3 yrs younger than Shelly so use S-3

S +M = 75

replace M with S-3 to get:

S +S-3=75

2S=78

s=39

So shelly is 39

Michelle is 3 years younger = 39-3 = 36


4 0
3 years ago
Read 2 more answers
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
BaLLatris [955]

Answer:

A.) 1508 ; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

General form of an exponential model :

A = A0e^rt

A0 = initial population

A = final population

r = growth rate ; t = time

1)

Using the year 1750 and 1800

Time, t = 1800 - 1750 = 50 years

Initial population = 790

Final population = 980

Let's obtain the growth rate :

980 = 790e^50r

980/790 = e^50r

Take the In of both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this rate, let predict the population in 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788 ; 1508 million people

In 1950;

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467 ; 1870 million people

2.)

Exponential model. For 1800 and 1850

Initial, 1800 = 980

Final, 1850 = 1260

t = 1850 - 1800 = 50

Using the exponential format ; we can obtain the rate :

1260 = 980e^50r

1260/980 = e^50r

Take the In of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Using the model ; The predicted population in 1950;

In 1950;

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571 ; 2083 million people

3.)

1900 1650

1950 2560

t = 1900 - 1950 = 50

Using the exponential format ; we can obtain the rate :

2560 = 1650e^50r

2560/1650 = e^50r

Take the In of both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using the model ; The predicted population in 2000;

In 2000;

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787 ; 3972 million people

3 0
3 years ago
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It's nothing because e=mc^2
4 0
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bixtya [17]
One of the easier approaches would be that of x- and y-intercepts.

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Plot these 2 points.  Then draw a str. line thru these points.
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4 years ago
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