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2 years ago

How do I find the function rule??? x: 0, 1, 2, 3 y: 5, 4, 3, 2

Mathematics

1 answer:

Makovka662 [10]2 years ago

8 0

Answer: y=-1x+5

Step-by-step explanation:

1. Use slope-intercept formula (y = mx + b) to find the slope which is represented by the variable 'b'.

m = ∆y / ∆x

m = -1 / 1

m = -1

y= -1x + b

2. Use any cooresponding x and y values to substitute into the formula. Ex: (x,y) → (1,4)

y = mx + b

4 = -1(1) + b

4 = -1 + b

5 = b

3. Plug in the values found into the formula.

y = -1x + 5

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Answers:

10.) $\displaystyle \pm{5}$

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Step-by-step explanations:

10.) $\displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}$

9.) $\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}$

8.) $\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

7.) $\displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

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I am joyous to assist you at any time.

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