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olchik [2.2K]
2 years ago
13

How do I find the function rule??? x: 0, 1, 2, 3 y: 5, 4, 3, 2

Mathematics
1 answer:
Makovka662 [10]2 years ago
8 0

Answer: y=-1x+5

Step-by-step explanation:

1. Use slope-intercept formula (y = mx + b) to find the slope which is represented by the variable 'b'.

m = ∆y / ∆x

m = -1 / 1

m = -1

y= -1x + b

2. Use any cooresponding x and y values to substitute into the formula. Ex: (x,y) → (1,4)

y = mx + b

4 = -1(1) + b

4 = -1 + b

5 = b

3. Plug in the values found into the formula.

y = -1x + 5

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Answer:

(-12,0)

Step-by-step explanation:

(-12,0)

(-4,2)

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Step-by-step explanation:

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y - 19 = - \frac{6}{10}(x - (-5))

y - 19 = - \frac{6}{10}(x+5)

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What is the volume of the following rectangular prism?
djverab [1.8K]

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Step-by-step explanation:

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2 years ago
Read 2 more answers
IaI − IbI + IcI , if a=−8; b=−5; c=1<br><br>pLEEEEEEZE hELP
yawa3891 [41]

Answer:

4

Step-by-step explanation:

to solve | a | - | b | + | c | we need to plug in the given values

a = -8

b = -5

c = 1

the | | bars mean absolute value which is the exact value a number is away from 0 on a number line. an absolute value has to be positive, not a negative, as you cant be negative spaces away from something. plugging in the values into the equation we have:

| -8 | - | -5 | + | 1 |

the absolute value of -8 is 8, as -8 is 8 units away from 0 on a number line

like wise with -5, the absolute value of -5 is 5, as -5 is 5 units away from 0 on a number line

1 is the absolute value of 1 as its 1 unit away from 0 on a number line

the new expression looks like the following:

8 - 5 + 1

now we just add/subtract

8 -5 = 3

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the solution to this expression is 4

6 0
3 years ago
Simplify the following expression using imaginary numbers. Express your answer in a + bi form
mamaluj [8]
<h2>Answer:</h2>

0 - 17i

<h2>Step-by-step explanation:</h2>

Given expression;

i⁸⁰ + i³⁸ - i17

To express the expression in the form a+bi;

<em>i. Rewrite the expression such that it contains terms in i²</em>

(i²)⁴⁰ + (i²)¹⁹ - i17

<em>ii. Solve the result from (i) above using the identity i² = -1</em>

We know that the square root of -1 is i. i.e

\sqrt{-1} = i

<em>Squaring both sides gives</em>

<em>=> </em>(\sqrt{-1} )^{2} = i^{2}<em />

=> -1 = i²

Therefore,

i² = -1

<em>Substitute i² = -1 in step (i) above</em>

(-1)⁴⁰ + (-1)¹⁹ - i17

<em>(iii) Solve the result in (ii)</em>

We know that the when a negative number is raised to the power of an even number, the result is a positive number. If it is raised to the power of an odd number, the result is a negative number. Therefore,

(-1)⁴⁰ + (-1)¹⁹ - i17 becomes

1 + (-1) - i17

0 - i17

<em>(iv) Write the result from (iii) in the form a+bi</em>

0 - 17i

5 0
3 years ago
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