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pshichka [43]
3 years ago
10

The score distribution shown in the table is for all students who took a yearly AP statistics exam. An AP statistics teacher had

48 students preparing to take the AP exam. Though they were obviously not a random​ sample, he considered his students to be​ "typical" of all the national students.​ What's the probability that his students will achieve an average score of at least​ 3?
Mathematics
1 answer:
Juliette [100K]3 years ago
3 0

Answer:

Probability that his students will get at least 3 is 0.9875

Step-by-step explanation:

In the given scenario the number of favorable outcomes are 3 out of 5 that  is 3,4,5 out of five.

  Probability = no of favorable outcomes/ sample space  

Probability his students will get 3 or more = 3/5/48= 0.6/48= 0.0125

Probability of at least getting 3 or more = 1- Probability of getting 3 or more

Probability that his students will getting at least 3 = 1- P( 3 or more)

                                                                                  = 1- 0.0125

                                                                                     = 0.9875

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A 50 ft flagpole is mounted to the top of a building. If the angle of elevation from a spot on the street to the top of the pole
monitta

Answer:

the height of the building = 91.67161722 feet.

Step-by-step explanation:

Suppose the height of the building (BC) = X feet.

A 50 ft flagpole (AB) is mounted to the top of a building.

So, height of the top of flag above the ground (AC) = (X+50) feet.

If the angle of elevation from a spot (P) on the street to the top of the pole is 58 degrees and the angle of elevation from the same spot (P) to the bottom of the pole is 46 degrees.

It means ∠APC = 58° and ∠BPC = 46°.

Considering Right triangle ΔACP, cot(∠APC) = PC / AC.

PC = AC*cot(∠APC) = (X+50)*cot(58°)

Considering Right triangle ΔBCP, cot(∠BPC) = PC / BC.

PC = BC*cot(∠BPC) = X*cot(46°)

We have PC = PC.

X*cot(46°) = (X+50)*cot(58°)

0.965688774 * X = 0.624869351 * (X+50)

(0.965688774 - 0.624869351) * X = 0.624869351 * 50

0.340819422 * X = 31.2434676

X = 31.2434676 / 0.340819422 = 91.67161722 feet.

Hence, the height of the building = 91.67161722 feet.

6 0
3 years ago
A dart hits the circular dartboard shown below at a random point. Find the probability that the dart lands in the shaded square
PtichkaEL [24]

Answer:

The first thing you need to do is, have a square whose area is 11² = 121 square inches. Then we are going to multiply the radius by π which is 3.14 the area of the circle with the radius 4 is equal to 3.14 × 4² = 3.14 × 16 = 50.24, you need to divide the calculated radius times π (3.14) you can get the answer and you need to round your answer to the nearest hundredth probability that the dart will hit within the circle is equal to 50.24 ÷ 121 = 0.4152066116 which is rounded to 0.04152 or 41.52% this assumes the dart will always hit the square at least.

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2 years ago
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
A store buys cell phones from the manufacturer for $34.40 and marks them up by 85%. What is the sale price of the phones in the
Gnom [1K]

Answer:

$5.16

Step-by-step explanation:

34.40 divided by .85 is 29.24. Subtract the diffrence of 34,40 and 29.24 which is $5.16. Hope this helps :)

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Your school is having a spring festival. Admission into the festival is $2 and each game inside the carnival costs $.75. How man
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Answer:

100 games .

Step-by-step explanation:

$15 / $.75 (the amount for each game) = 100 games .

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