Answer:
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
Explanation:
Let the cost for ribeye steak dinners be m and cost for grilled salmon dinners be n.
A waitress sold 10 ribeye steak dinners and 18 grilled salmon dinners, totaling $590.39 on a particular day.
So, we have
10 m + 18 n = 590.39 -------equation 1
Another day she sold 22 ribeye steak dinners and 9 grilled salmon dinners, totaling $583.49
So, we have
22 m + 9 n = 583.49 -------equation 2
equation 2 x 2
44 m + 18 n = 1166.98 -------equation 3
equation 3 - equation 1
44 m + 18 n - ( 10 m + 18 n ) = 1166.98 - 590.39
m = 16.96 $
Substituting in equation 1
22 x 16.96 + 9 n = 583.49
n = 23.37 $
a) The cost of ribeye steak dinners is $ 16.96.
b) The cost of grilled salmon dinners is $ 23.37.
There are four numbers of 3-coin combinations if we can choose from nickels, dimes, quarters, and half-dollars.
<h3>How to solve probability combinations?</h3>
The coins to select from are nickels, dimes, quarters, and half-dollars;
Thus;
Coins (n) = 4
The number of coin to select is:
Coin (r) = 3
The coin combination is then calculated using:
Combination = ⁴C₃
Apply the combination formula, we have;
Combination = 4
Thus, there are four number 3-coin combinations if we can choose from nickels, dimes, quarters, and half-dollars.
Read more about combinations at; brainly.com/question/4658834
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Just multiply the tops together and the bottoms together :)
