Answer:
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
H(X)=5.4224 bits per symb
H(X|Y="not C")=0.54902 bits per symb
Explanation:
P(B)=2P(C)
P(A)=2P(B)
But
P(A)+P(B)+P(C)=1
4P(C)+2P(C)+P(C)=1
P(C)=1/7
Then
P(A)=4/7
P(B)=2/7
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
iii
If X={A,B,C}
and P(Xi)={4/7,2/7,1/7}
where Id =logarithm to base 2
Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}
=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}
=5.4224 bits per symb
if P(C) =0
P(A)=2P(B)
P(B)=1/3
P(A)=2/3
H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)
=0.54902 bits per symb
Answer and Explanation:
top level class can not be declare as private or protected. It is always public. If we declare a top level class as private then the compiler always complain that the private is not allowed and if we declare top level class as protected then compiler complain that modifier protection is not allowed here. so we can not declare top level class as private or protected
In C++, 'Try block' comprises of a group of statements in which there is a probability of an exception to take place.
C). The statements that would be left in the try block in case a particular statement leads to an exception 'can't be executed.'
- In case an exception takes place, the left statements in the try block fail to function.
- This is the primary reason for which a catch block immediately succeeds a try block in order to deal with the exception and help close that code to allow the statements to work.
- Thus, <u>option C</u> is the correct answer.
Learn more about 'Try block' here:
brainly.com/question/14186450
