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2 years ago

Please! please! Anyone could help me with 8th Grade Math?!?

Mathematics

2 answers:

Katena32 [7]2 years ago

5 0

Answer:

it is not a quadratic equation

Step-by-step explanation:

look at the picture

Fantom [35]2 years ago

3 0

Answer:

How do you find the sum of factors of a quadratic equation?

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C r = -2 - u s = -2 + u Two numbers r and s sum up to -4 exactly when the average of the two numbers is \frac{1}{2}*-4 = -2.

How do you solve a quadratic equation?

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

Step-by-step explanation:

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I have to solve these using area models:

melamori03 [73]

30 x 24 there you gooooooo

8 0

3 years ago

A-2=-1 + 2a-4-1 send me the work please! (solving equations with variables on both sides)

Vladimir [108]

The value of "a" is 4

Solution:

Given expression is:

$a - 2 = -1 + 2a - 4-1$

The above expression involves variables and constants

A variable is a symbol that represents an unknown number

Here the variable is "a"

Constants are fixed numbers like 1, 2 etc

From given expression:

$a - 2 = -1 + 2a - 4-1$

Move the varibale "2a" from right side to left side of equation

When, 2a is moved from R.H.S to L.H.S, it becomes -2a

$a -2a - 2 = -1 -4-1$

Now move the constant -2 from left side to right side of equation

Similarly, when -2 is moved from L.H.S to R.H.S, it becomes +2

$a-2a = -1-4-1+2$

Now add the variables on left side of equation

$-a = -1-4-1+2$

Now add the constants on right side of equation

$-a = -6+2\\\\-a = -4$

Cancel the negative sign on both sides of equation

$a=4$

Thus the value of "a" is 4

6 0

3 years ago

You have just enough coins to pay for a loaf of bread priced at $1.95. You know you have a total of 12 coins, with only quarters

blondinia [14]

4+8=12 0.10 4F BY FGGH

5 0

3 years ago

Let v1=(2,-6) and v2=(-4,7)

seropon [69]

The magnitude of each vector is the Pythagorean sum of its components.

a. |v1| = √(2² + (-6)²) = √40 = 2√10

|v2| = √((-4)² + 7²) = √65

b. To make each vector into a unit vector, divide each component by the vector's magnitude.

u1 = v1/|v1| = (2/(2√10), -6/(2√10))

u1 = (√10/10, -3√10/10)

u2 = v2/|v2| = (-4/√65, 7/√65)

u2 = (-4√65/65, 7√65/65)

8 0

3 years ago

A) The perimeter of a rectangle is the sum of the lengths of its four sides. Write an expression for the perimeter of the rectan

goblinko [34]

Answer:

Below

Step-by-step explanation:

The length of this triangle is 3x+1 and the width is x.

The perimeter P is:

P= 2(3x+1)+2*x

P= 6x+2+2x

P= 8x+2

Let's evaluate it when x=1/2

●1/2 =0.5

P= 8*0.5+2 =4+2= 6 ft

●●●●●●●●●●●●●●●●●●●●●●●●

The area A is:

A = (3x+1)*x

A= 3x^2 +x

Let's evaluate it when x=0.5 feet

A= 3*0.5^2 +0.5

A= 3*0.25+0.5

A= 0.75 +0.5

A= 1.25 ft^2

6 0

3 years ago