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Ket [755]
2 years ago
13

Please classify the real number: 9.63 with 63 being repeated

Mathematics
2 answers:
prisoha [69]2 years ago
7 0

Answer:

Step-by-step explanation:

9.63636363636363636363636363

strojnjashka [21]2 years ago
5 0

Answer:

Wouldn't it be 9.6363636363?

comment on this for further help

Step-by-step explanation:

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a recipe uses 1 1/4 cups of milk to make 10 servings. if the same amount of milk is used for each serving, how many servings can
Anestetic [448]

Answer:

128 servings can be made using 1 gallon of milk.

Step-by-step explanation:

Given that:

1\frac{1}{4} cups of milk make 10 servings

1\frac{1}{4} can also be written as 1.25

Ratio of cups of milk to servings = 1.25 : 10

1 gallon = 16 cups

Let,

x be the number of servings made from 1 gallon

Ratio of cups of milk to servings = 16 : x

This is a direct proportion

1.25 : 10 :: 16 : x

Product of mean = Product of extreme

10*16 = 1.25x

160 = 1.25x

1.25x=160

Dividing both sides by 1.25

\frac{1.25x}{1.25}=\frac{160}{1.25}\\x=128

Hence,

128 servings can be made using 1 gallon of milk.

3 0
3 years ago
Find the volumes of the solids generated by revolving the triangle with vertices (2, 2)​, (2, 6)​, and (5, 6) about ​a) the​ x-a
Vesna [10]
  • About the x-axis (washer method):

\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}

  • About the y-axis (shell method):

\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}

  • About x=7 (shell method):

\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}

  • About y=2 (washer method):

\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}

7 0
3 years ago
Directions: Solve these equations by using addition. You will need to use your fraction and decimal skills to solve these
Marina CMI [18]
One simple way to approach this is to subtract the number that DOESN’T have the variable with the solution by the sum.
Lets use problem 1 as the example:
1.) N+8=13
In this case, we subtract 13 by 8 and get 5, therefore N= 5.

2.) B+17=62
62-17= 45
B= 45

3.) X+5/6= 7/16
7/16-5/6= -19/48
X= -19/48

4.) y+1/7=5/8
5/8-1/7= 27/56
Y= 27/56

5.) 14+y=69
69-14=55
Y=55

6.) c+3.6=4.9
4.9-3.6=1.3
C= 1.3

Now for the word problems:
Lets use 7 as the example-
7.) a number increased by 19 is equal to 221.
Since we don’t know the number being increased by 19, that will be our variable. It will be re-written as so:

N + 19 = 221

Where N is the unknown number.

Using the same method of subtracting by the sum and the number that’s not the variable, we’ll get the solution to N
221-19= 202
N= 202

8.) N + 1 2/3 = 8
8 - 1 2/3 = 19/3= 6 1/3
N= 6 1/3

I really hope this helps
6 0
2 years ago
The integers greater than -3and less than 4​
Semmy [17]

Answer:

-2 -1 0 1 2 3

Step-by-step explanation:

7 0
2 years ago
Determine the degree of the relation y = 8x^4 – 3x^3 + x^2.<br><br> a) 4<br> b) 3<br> c) 1<br> d) 2
BlackZzzverrR [31]

Answer:

x= 2x+3

Step-by-step explanation:

delta= postif

x1= -b - racine de Delta sur A AU CARRE

x2= -b + racine de delta A AU CARRE

8 0
2 years ago
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