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2 years ago

△ABC is a right isosceles triangle, the centers of two arcs are the midpoint of AB

Mathematics

1 answer:

mel-nik [20]2 years ago

4 0

Answer:

Step-by-step explanation:

Let's define 3 areas:

S = area of semicircle with radius 6 in (diameter AB)
T = area of quarter circle with radius 6√2 in (radius AC)
U = area of triangle ABC (side lengths 6√2)

The white space between the "moon" and the triangle has area ...

white = T - U

Then the area of the "moon" shape is ...

moon = S -white = S -(T -U) = S -T +U

The area we're asked to find is ...

moon - triangle = (S -T +U) -U = S -T

The formula for the area of a circle of radius r is ...

A = πr²

So, ...

S = (1/2)π(6 in)² = 18π in²

and

T = (1/4)π(6√2 in)² = 18π in²

The difference in areas is S -T = (18π in²) -(18π in²) = 0.

There is no difference between the areas of the "moon" and the triangle.

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In 1999 bus fare in atlanta was 4.70.In 1979 the fare was 2/5 of the fare in 1999 what was the fare in 1979

Gennadij [26K]

Answer : 1.96 was the fare in 1979.

Explanation :

Bus fare in Atlanta in 1999 =4.70

$\text{As we have given that in 1979 the fare was } \frac{2}{5} \text{ of the fare in 1999.}$

$\text{Bus fare in Atlanta in 1979=} \frac{2}{5}\times 4.70$

Bus fare in Atlanta in 1979 is given by

$\frac{2\times 4.70}{5}\\\\=\frac{9.80}{5}\\\\=1.96$

∴ 1.96 was the fare in 1979.

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2 years ago

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tamaranim1 [39]

Answer:

Option 2

Step-by-step explanation:

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2 years ago

First determine the missing angle for triangle 1 and triangle 2. Then apply the angle-angle criterion to determine if the two tr

barxatty [35]

Answer:

Triangle 1 – ∠1 = 25°, ∠2 = 115° Triangle 2 – ∠1 = 25°, ∠3 = 40°
Triangle 1 – ∠1 = 5°, ∠2 = 15° Triangle 2 – ∠2 = 15°, ∠3 = 160°

Step-by-step explanation:

You can save yourself some trouble if you realize that one of the angles in one pair must match one of the angles in the other pair.

This observation eliminates the first two choices.

Going further, the triangles will be similar if the dissimilar angles together with one of the similar angles totals 180°.

Triangle 1 – ∠1 = 50°, ∠2 = 30°

Triangle 2 – ∠2 = 20°, ∠3 = 100° . . . . . no angles match

Triangle 1 – ∠1 = 60°, ∠2 = 20°

Triangle 2 – ∠1 = 40°, ∠3 = 100° . . . . . no angles match

Triangle 1 – ∠1 = 25°, ∠2 = 115°

Triangle 2 – ∠1 = 25°, ∠3 = 40° . . . . 25° angles match; 25+40+115 = 180

These triangles are similar.

Triangle 1 – ∠1 = 5°, ∠2 = 15°

Triangle 2 – ∠2 = 15°, ∠3 = 160° . . . . 15° angles match; 15+5+160 = 180

These triangles are similar.

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The graph is shown in the attached image.

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