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Leona [35]
3 years ago
6

What are the complex solutions of 2x^2+x+6=0

Mathematics
2 answers:
attashe74 [19]3 years ago
8 0
Lets use quadratic formula:

x=\frac{-1+- \sqrt{1-4*2*6} }{4}= \frac{-1+- \sqrt{-47} }{4}= \frac{-1+-i \sqrt{47} }{4}
x₁=\frac{-1+i \sqrt{47} }{4}
x₂=\frac{-1-i \sqrt{47} }{4}


stepan [7]3 years ago
6 0
2x² + x + 6 = 0
x = <u>-(1) +/- √((1)² - 4(2)(6))</u>
                    2(2)
x = <u>-1 +/- √(1 - 48)</u>
                 4
x = <u>-1 +/- √(-47)
</u>               4
x = <u>-1 +/- i√(47)
</u><u /><u />               4<u>
</u>x = <u>-1 + i√(47)</u>              x = <u>-1 - i√(47)
</u><u />              4                                 4
x = -0.25 + 0.25i√(47)      x = -0.25 - 0.25i√(47)
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_________________________________________________________

Step-by-step explanation:

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