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1 year ago

14

What is the volume of this figure

1 answer:

Harrizon [31]1 year ago

7 0

Answer:

1152 is the volume

Step-by-step explanation:

you welcome

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Please help me, picture below.

Lesechka [4]

The answer is the last one, 8 square root 6 because when factoring out 486 you will get 9 square root 6. When factoring out 24, you will get 2 square root 6 and the 6 is already factored out. After that you add and subtract and you will get the last answer 8 square root 6. Hope that helped.

8 0

2 years ago

Which quadratic equation is equivalent to (x + 2)^2 + 5(x + 2) - 6 = 0?

Ber [7]

Answer:

$x^2$ + 9x + 8 = 0

Step-by-step explanation:

First, we have to simplify this quadratic equation:

(x+2)^2 + 5(x+2) - 6 = 0

x^2 + 4x + 4 + 5x + 10 - 6 = 0

x^2 + 9x + 8 = 0

5 0

1 year ago

Daniel [21]

Answer:

d) 192

Step-by-step explanation:

Your calculator can do this for you.

Or, you can simplify to

$12\cdot\dfrac{4^{-2}}{4^{-4}}=12(4^{-2+4})=12(4^2)=192$

3 0

3 years ago

What is 24^3 - 9 + 8? Factorize if possible please!

Ahat [919]

Answer:

13,823

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1

Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let $r$ represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

$\frac{dr}{dt}=7\ mm/hr$

Volume of cylinder is given by:

$V=\pi\ r^2h$

Finding derivative of the Volume with respect to time.

$\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}$

Plugging in the values given:

$\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)$

$\frac{dV}{dt}=252\pi$

Using $\pi=3.14$

$\frac{dV}{dt}=252(3.14)$

$\frac{dV}{dt}=791.28\ mm^3/hr$ (Answer)

Thus rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

6 0

2 years ago