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Naya [18.7K]
1 year ago
13

Y = x^2 - 4 y= x + 2

Mathematics
1 answer:
Snezhnost [94]1 year ago
5 0
Hopes this help:

Answer: x = 3, -2 & y = 5, 0

Hopes this is the answer that you where looking for if not I am so sorry.
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(x-5)(-2) Please help, need awnser by thursday
Amiraneli [1.4K]

Answer:

−2+10

Step-by-step explanation:(

5 0
2 years ago
Does anyone know how to finish this equation?
nikdorinn [45]
Not sure what you mean?
6 0
2 years ago
If a car drove 180 miles in 3 hours and a truck drove 150 miles in 2 hours, what is the speed (in miles per hour) of the faster
grigory [225]

Step-by-step explanation:

Divide 180 by 3 = 60

Divide 150 by 2 = 75

The faster vehicle is truck and its speed is 75 mph

6 0
2 years ago
The length of a rectangle is 4 more than 3 times the width if the perimeter of the rectangle is 18.4 cm what is the area of the
garik1379 [7]
Let's call the width: w

the lenght is then 3w+4 ("4 more than 3 times the width")

and the parameter would be 2(w+3w+4), that is 2*(4w+4), that is 8w+8.

this is also equal to 18.4:

8w+8=18.4
8w=10.4
w=1.3

this is the width, and the lenght is:
4+3*1,3=4+3.9=7.9

and the area is their product:
1.3*7.9=10.27
6 0
3 years ago
10. A 266-hp output is required for an engine. If there is a 5% loss of power, what amount of input
marta [7]

Answer:

Amount of input horsepower needed is 279.3 hp.

Step-by-step explanation:

if there is a loss of power of 5% the base horsepower will need to be increased by same percentage so that same amount of power can be delivered.

Now to calculate 5% of 266 hp, we can write

266 ×\frac{5}{100} = 13.3 hp

Now to deliver same amount of power we will have to add 5% of 266 hp to its actual power.

So real base power which is needed to deliver 266hp output even at a loss of 5% will be = (266+13.3) hp = 279.3 hp

To know more about horsepower and percentage problem:

brainly.com/question/24585630

7 0
2 years ago
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