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WILL GIVE BRAINLY Find the perimeter of the figure below, in meters.

yan [13]

Answer:

$147.6\:\mathrm$

Step-by-step explanation:

The perimeter of a polygon is simply sum of the lengths of all sides of the polygon.

Therefore, we can find this polygon's perimeter by adding up the length of each of its sides:

$9.8+9.8+11.7+9.8+21.5+21+11.7+9.8+31.3+11.2=\boxed{147.6\:\mathrm{m}}$

Since there is a lot to keep track of, I'd recommend picking any side and moving clockwise/counter-clockwise until you get all sides.

3 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

The square root of 68 is between what two consecutive whole numbers

Pavel [41]

The two consecutive numbers are 8 and 9.

4 0

4 years ago

A local restaurant offers a deal if you purchase 3 medium pizzas you get 2 side dishes for free if you get a total of 8 side dis

Margarita [4]

11 you count by 3 with the pizzas and 2 with the side dishes

5 0

4 years ago

What is the mean absolute deviation of the following data set

tatuchka [14]

Answer:

4.32

Step-by-step explanation:

First, we have to find the mean of the data set.

16, 11, 9, 12, 11, 10, 10, 8, 15, 0, 2, 15, 14, 7, 11, 5, 14, 20, 3, 11, 13, 7, 0, 5, 21 all added together equals 250. 250 divided by 25 = 10. So 10 is the mean.

Now we have to find the absolute distances of each number from the mean.

16 - 10 = 6... 11 - 10 = 1... so on, giving us this -->

6, 1, 1, 2, 1, 0, 0, 2, 5, 10, 8, 5, 4, 3, 1, 5, 4, 10, 7, 1, 3, 3, 10, 5, 11

Finally, we have to find the mean of the distances (which is done by adding all the numbers above and dividing the sum by the number of values there are).

108 divided by 25 = 4.32.

So, 4.32 is the mean absolute deviation (MAD) of the following data set.

4 0

3 years ago

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