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wolverine [178]
2 years ago
12

Answer answer please answer

Mathematics
2 answers:
kiruha [24]2 years ago
6 0

is equal to

=

hope it helps...!!!

Dafna11 [192]2 years ago
4 0

Answer:

Your answer would be C, =

Step-by-step explanation:

I got the answer wrong so go off of the other persons.

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A recipe calls for 1/2 cup sugar and 1 cup flour. How much flour will you need if you use 1 cup of sugar?
nadya68 [22]
You would need 2 cups of flour. It’s just multiplying by 2.
7 0
3 years ago
For the proportional relationship y = -5x, what is the ratio of vertical change to horizontal change? Will the graph of the line
NeTakaya
The given proportional relationship is y = -5x.
Therefore the ratio
y/x = -5 = -5/1

If x changes by 1, then y/x = y/1 = -5.
This means that y changes by -5 when x changes by 1.
The ratio of vertical change is -5:1

The standard equation for a straight line is
y = m*x + c
where
m = the slope,
c = the y-intercept.

Therefore the given relationship is a straight line with a negative slope of -5. This means that y decreases as x increases.

Answer: C
-5:1
The graph decreases from left to right.
6 0
4 years ago
Mike is traveling to the beach 30 miles away from his house. On Mike's
Andre45 [30]

Answer:

A. 1 inch = 6 miles

Step-by-step explanation: We need to divide 30 by 5 to see how much 1 inch equals. 30÷5=6. We now known 1 inch = 6 miles.

7 0
3 years ago
Read 2 more answers
6 ( 7y - 5) simplified
dmitriy555 [2]

Answer:

42y-30

Step-by-step explanation:

here you go

3 0
3 years ago
Which is the equation of a hyperbola with directrices at y = ±2 and foci at (0, 4) and (0, −4)?
Advocard [28]

Answer:

Step-by-step explanation:

First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.

If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.

After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form

y = ±\frac{a}{b}(x-h)+k

Filling in our asymptotes as they were given to us:

y = ±\frac{2}{1}(x-0)+0 where a is 2 and b is 1. Now we can write the formula for the hyperbola!:

\frac{(y-0)^2}{4}-\frac{(x-0)^2}{1}=1 which of course simplifies to

\frac{y^2}{4}-\frac{x^2}{1}=1

4 0
4 years ago
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