Question

The equation -16t^2 + 26" align="absmiddle" class="latex-formula">​ represents the height (in feet) of a water balloon t​ seconds after it is dropped. Approximate the time it takes the water balloon to reach the ground to the nearest tenth.

Answer 1

The answer would be 1:3 seconds make sure to double check the work but I’m 100% sure that’s what it is

Answer 2

Answer:  1.3 seconds

Explanation:

Replace h with 0. Solve for t.

$h = -16t^2 + 26\\\\0 = -16t^2 + 26\\\\16t^2 = 26\\\\t^2 = 26/16\\\\t^2 = 1.625\\\\t = \sqrt{1.625}\\\\t \approx 1.2748\\\\t \approx 1.3$

It takes about 1.3 seconds for the balloon to hit the ground.