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Ivan
3 years ago
9

C. Find the 4th term in the expansion of (y + 2)

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0
What is the binomial raised to? you can’t do this problem without it
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Show working <br> (Y-4) (y+9)=
gladu [14]

Answer:

y^{2} + 5y - 36

Step-by-step explanation:

(y-4)(y+9) = y^{2} + 9y - 4y - 36

=  y^{2} + 5y - 36

hope this helps! :D

have a miraculous day!! <3

7 0
3 years ago
A scale on a map shows that 2 inches = 25 miles.
Mumz [18]
Part A : it would be 4.8 inches
Part B : 1/4 inch would equal 3.125
4 0
3 years ago
Read 2 more answers
Give that y=-4,x=3,b=7 &amp; c=2 find b^c​
disa [49]

Answer:

49

Step-by-step explanation:

b^c

Let b = 7 and c = 2

7^2

7*7 = 49

7 0
3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Archy [21]
Each quarter of a set of data is denoted by a quartile:

The 25th percentile makes up the first quartile Q1.
The 50th percentile represents the second quartile Q2.
The 75th percentile is the third quartile, or Q3.
Finding the second quartile, Q2, is simple. It divides an ordered data set into upper and lower half and is the median of any data set.

The median of the bottom half, excluding the value of Q2, makes up the first quartile, or Q1. The median of the upper half, excluding the value of Q2, makes up the third quartile, or Q3.

Sort the values in your data set from lowest to highest.
the median, please. Q2 stands for the second quartile.
Divide the ordered data collection in half at Q2.
The median of the lower half of the data makes up the lower quartile Q1.
The median of the data's upper half represents the upper quartile Q3.
When determining the first and third quartiles, omit the median if the size of the data set is unusual.
The median, if the size of the data collection is even, is the average of the middle two values. Add the two figures together, then divide by two. The value of the median, which divides the data set into lower and higher half, is

How to Find Interquartile Range
The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.

IQR = Q3 - Q1

How to Find the Minimum

The minimum is the smallest value in a sample data set. Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:

Min=1=min()=1

How to Find the Maximum

The maximum is the largest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn. The formula for maximum is:

Max==max()=1

How to Find the Range of a Set of Data

The range of a data set is the difference between the minimum and maximum. To find the range, calculate xn minus x1.

=−1

So to Answer your question


6 0
2 years ago
Someone please answer 2x(3x-8) =
olga2289 [7]

Answer:

Simplifying

2x(3x + -8) = 0

Reorder the terms:

2x(-8 + 3x) = 0

(-8 * 2x + 3x * 2x) = 0

(-16x + 6x2) = 0

Solving

-16x + 6x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.

2x(-8 + 3x) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve:

Simplifying

x = 0

Solving

x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying

x = 0

Subproblem 2

Set the factor '(-8 + 3x)' equal to zero and attempt to solve:

Simplifying

-8 + 3x = 0

Solving

-8 + 3x = 0

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.

-8 + 8 + 3x = 0 + 8

Combine like terms: -8 + 8 = 0

0 + 3x = 0 + 8

3x = 0 + 8

Combine like terms: 0 + 8 = 8

3x = 8

Divide each side by '3'.

x = 2.666666667

Simplifying

x = 2.666666667

Solution

x = {0, 2.666666667}

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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