Explanation:
Molar mass
The mass present in one mole of a specific species .
The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .
(a) )hydrogen fluoride, HF
Since ,
Molar mass of of the atoms are -
Hydrogen , H = 1 g/mol
Fluorine, F = 19 g/mol.
Molar mass of HF = ( 1 g/mol ) + ( 19 g/mol ) = 20 g/mol.
(b) ammonia, NH₃
Molar mass of of the atoms are -
nitrogen, N = 14 g/mol
and Hydrogen , H = 1 g/mol
Molar mass of NH₃ = 14 + ( 3 x 1 ) g/mol = 17 g/mol.
(c) nitric acid , HNO₃
Molar mass of of the atoms are -
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
nitrogen, N = 14 g/mol
Molar mass of HNO₃ = (1 g/mol ) + ( 14 g /mol) + ( 3 x 16 ) = 63 g/mol.
(d)Silver sulfate, Ag₂SO₄
Molar mass of of the atoms are -
silver, Ag = 108 g/mol
sulfur, S = 32 g/mol.
oxygen , O = 16 g/mol.
molar mass of Ag₂SO₄ = ( 2 x 108 g/mol ) + ( 32 g /mol )+ (4 x16 g/mol )
=312 g/mol.
(e )boric acid , B(OH)₃
Molar mass of of the atoms are -
boron , B = 11 g/mol
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molar mass of B(OH)₃ = ( 11 ) + ( 3x16 ) + ( 3 x 1 ) = 62 g/mol.
The complete balanced chemical reaction for this is:
C6H8O7 + 3 NaHCO3 ---> 3 H2O + 3 CO2 + Na3C6H5O7
First calculate for the number of moles of each reactant.
moles C6H8O7 = 1 g / (192.124 g / mol) = 5.2 * 10^-3 mol
moles NaHCO3 = 1 g / (84.01 g / mol) = 11.9 * 10^-3 mol
A. The ratio of the reactant from the chemical reaction
is 3NaHCO3:1C6H8O7, while the given chemicals are in the ratio of:
11.9 * 10^-3NaHCO3: 5.2 * 10^-3 C6H8O7 =
2.29NaHCO3:1C6H8O7
Therefore this means that there is less amount of NaHCO3
supplied than what is required therefore the limiting reactant is:
NaHCO3
B. We calculate based on the limiting reactant.
mass CO2 = 11.9 * 10^-3 mol NaHCO3 (3 mol CO2/1 mol
NaHCO3) (44.01 g/mol)
mass CO2 = 1.57 g
C. I believe what is asked here is the amount of excess
reactant which remains. The excess reactant is C6H8O7.
mass C6H8O7 left = [5.2 * 10^-3 mol – (11.9 * 10^-3 mol
NaHCO3 (1 mol C6H8O7/ 3 mol NaHCO3))] * (192.124 g / mol)
mass C6H8O7 left = 0.237 g
Answer:
"True"
Explanation:
Breathing released by humans is naturally acidic. When humans inhale, there are also dangerous toxic substances such as carbon dioxide in the lungs inside the human body, which are neutralized with the help of HCl hydrochloric acid, but due to hydrochloric acid, the breath that man leaves becomes acidic.
B. A sample of oxygen gas.
That's because Oxygen gas has a formula of O2 which is a compound, and it's a diatomic element, meaning it can form a compound by itself. So it's pure, and a compound.