Molar heat of vaporization is defined as the heat absorbed by one mole of substance to convert from liquid to gas.
<h3>How do you calculate the heat of vaporization?</h3>
The formula used to calculate the heat of vaporization is:
Where,
Q = Amount of Heat
n = number of moles of a substance
molar enthalpy of fusion
Now, to calculate the moles of methane:
Moles = 3.425 mol
Now, 1 mol of methane absorbs = 8.53 KJ
3.425 mol of methane absorbs = 
Thus, the energy is absorbed till the methane vaporizes at its boiling point is 29.1 KJ.
Learn more about <u>vaporization </u>here:
brainly.com/question/2491083
Answer:
pH = 2.5
Explanation:
Given data:
Concentration of HBr = 0.003 M
pH of solution = ?
Solution:
Formula:
pH = -log[H⁺]
by putting values,
pH = -log [ 0.003]
pH = 2.5
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Answer:
The reaction combines the sodium with the hydrogen and oxygen in water to form sodium hydroxide and hydrogen gas, and you get a lot of energy released as heat as well. This heat actually melts any remaining sodium that has not reacted yet, and ignites the hydrogen gas, so you get the bang and the flash.
Explanation:
