Answer:
29.41% of Calcium and 47.04% of Oxygen
Explanation:
The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.
The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:
13.61g / 46.28g * 100 = 29.41% of Calcium
And percent composition of Oxygen is:
21.77g / 46.28g * 100 = 47.04% of Oxygen
<u>Answer:</u> The molality of magnesium chloride is 1.58 m
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
![\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolality%7D%3D%5Cfrac%7Bm_%7Bsolute%7D%5Ctimes%201000%7D%7BM_%7Bsolute%7D%5Ctimes%20W_%7Bsolvent%7D%5Ctext%7B%20%28in%20grams%29%7D%7D)
Where,
= Given mass of solute (magnesium chloride) = 75.0
= Molar mass of solute (magnesium chloride) = 95.21 g/mol
= Mass of solvent = 500.0 g
Putting values in above equation, we get:
![\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m](https://tex.z-dn.net/?f=%5Ctext%7BMolality%20of%20%7DMgCl_2%3D%5Cfrac%7B75.0%5Ctimes%201000%7D%7B95.21%5Ctimes%20500.0%7D%5C%5C%5C%5C%5Ctext%7BMolality%20of%20%7DMgCl_2%3D1.58m)
Hence, the molality of magnesium chloride is 1.58 m
Answer:
Option A (9.0) is the correct alternative.
Explanation:
The given values are:
Molarity,
= 1.5 M
Volume,
= 6000 mL
or,
= 6 L
As we know,
⇒ ![Molarity=\frac{Moles}{Volume}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7BMoles%7D%7BVolume%7D)
or,
⇒ ![The \ moles \ of \ NaCl=Molarity\times Volume](https://tex.z-dn.net/?f=The%20%5C%20moles%20%5C%20of%20%5C%20NaCl%3DMolarity%5Ctimes%20Volume)
By putting the values, we get
![=1.5\times 6](https://tex.z-dn.net/?f=%3D1.5%5Ctimes%206)
![=9 \ mol](https://tex.z-dn.net/?f=%3D9%20%5C%20mol)
The 2 sources are solar and nuclear energy.
Atomic radius aka distance from the nucleus to the outermost energy level. The greater this distance, the less electrostatic attraction between these oppositely charged particles.