Earthquakes can cause all of the above.
trigger other earthquakes - when there is a large magnitude earthquake it
lead to shake the earth's surface. Thus it can create more earthquakes on the same place or neighboring places.
cause billions of dollars - when there is a large disturbance it can destroy big buildings, homes, etc. Which is basically a billion dollar loss.
cause tsunami - If there is a disturbance in the earth's surface near sea's, etc there is chance of tsunami.
The term of this sequence is:
<span>-(17/30)n^5+(113/12)n^4-(173/3)n^3+(1915/12)n^2-(5813/30)n+85 </span>
<span>Therefore,term number 7 is:-146/1=-146 </span>
The area of the resulting figure will be given by:
∫f(x)dx
f(x)=13/2x^3
thus
∫f(x)dx=13/2∫x³dx=13/8[x^4]
integrating over the inerval
13/8(12^4)-13/8(5^4)
=32680+3/8 sq. units
=
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths.
Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday.
Jan - Friday
Feb - Monday
Mar - Monday
Apr - Thursday
May - Saturday
Jun - Tuesday
Jul - Thursday
Aug - Sunday
Sep - Wednesday
Oct - Friday
Nov - Monday
Dec - Wednesday
Now let's count how many times for each weekday, the 13th falls there.
Sunday - 1
Monday - 3
Tuesday - 1
Wednesday - 2
Thursday - 2
Friday - 2
Saturday - 1
The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc.
So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get:
Jan - Friday
Feb - Monday
Mar - Tuesday
Apr - Friday
May - Sunday
Jun - Wednesday
Jul - Friday
Aug - Monday
Sep - Thursday
Oct - Saturday
Nov - Tuesday
Dec - Thursday
And the weekday totals are:
Sunday - 1
Monday - 2
Tuesday - 2
Wednesday - 1
Thursday - 2
Friday - 3
Saturday - 1
And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year.
And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
2, 8, 32, 128,
Multiply by 4 for each number
8/2= 4
32/8= 4
128/32= 4
128*4=512
512*4= 2,048
Answer: D 512, 2,048
