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mr_godi [17]
2 years ago
12

The average 8- to 18-year-old spends____ per day on average in front of a screen doing very little to

Mathematics
1 answer:
geniusboy [140]2 years ago
5 0

Answer:

3 hours or more

Step-by-step explanation:

why because of the games and entertainment

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Highest to lowest -0.6,0.38, -0.09, 0.7
algol13

Hey there!

Guide:

• NEGATIVES are BELOW zero

• POSITIVES are ABOVE zero

• DECIMALS are BELOW zero

Highest to lowest: –0.6, 0.38, –0.09, 0.7

0.7 ⬅️ HIGHEST

0.38 ⬅️ 2nd HIGHEST

–0.09 3rd HIGHEST ⬅️

–0.6 ⬅️ LOWEST

Answer: 0.7 , 0.38, –0.09, and –0.6 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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Reduce the rate 210 miles per 3 hours to it's unit rate and write the miles portion of your answer
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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

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-8 you have to do a number line
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