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3 years ago

Help me ..................

Mathematics

1 answer:

Law Incorporation [45]3 years ago

6 0

What is the question for the thing s

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What is the slope of the tangent line to f(x)=-2x+5 at x=-3

a_sh-v [17]

Answer:

is there a graph with t

Step-by-step explanation:

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3 years ago

What is the sum? 3k/k^2+k-7/4K

Aleksandr-060686 [28]

Answer:

$\dfrac{k^2+5k}{4k^2}$

Step-by-step explanation:

A suitable common denominator is 4k^2. (This eliminates the first and last choices.)

$\dfrac{3k}{k^2}+\dfrac{k-7}{4k}=\dfrac{4(3k)}{4(k^2)}+\dfrac{k(k-7)}{k(4k)}\\\\=\dfrac{12k+k^2-7k}{4k^2}=\boxed{\dfrac{k^2+5k}{4k^2}}$

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3 years ago

Stephen purchased a guitar, which was originally priced at $80 but

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$24

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3 years ago

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

The equation y = 5 represents the graph of a line perpendicular to the y-axis and passing through the point (1,5).

DedPeter [7]

Answer:

False

Step-by-step explanation:

A perpendicular line parallel to the y- axis has equation

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (1, 5) with x- coordinate 1, thus

x = 1 ← equation of perpendicular line

7 0

3 years ago

Read 2 more answers