we know that the square, 4 equal sides, has a perimeter of 24, meaning each sides is simply 24 ÷ 4 = 6, since the area of a square is simply the side², that means the area of the square is 6² or just 36. We also know that the the trapezium has double the area of the square, namely 2*36 = 72, Check the picture below.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8\\ a=AB\\ b=3AB\\ A=72 \end{cases} \implies \begin{array}{llll} 72=\cfrac{8(AB+3AB)}{2}\\\\ 72=4(4AB)\implies 72=16AB\\\\ \cfrac{72}{16}=AB\implies \cfrac{9}{2}=AB \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D8%5C%5C%20a%3DAB%5C%5C%20b%3D3AB%5C%5C%20A%3D72%20%5Cend%7Bcases%7D%20%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%2072%3D%5Ccfrac%7B8%28AB%2B3AB%29%7D%7B2%7D%5C%5C%5C%5C%2072%3D4%284AB%29%5Cimplies%2072%3D16AB%5C%5C%5C%5C%20%5Ccfrac%7B72%7D%7B16%7D%3DAB%5Cimplies%20%5Ccfrac%7B9%7D%7B2%7D%3DAB%20%5Cend%7Barray%7D)
Answer:
D.
Step-by-step explanation:
It's impossible to know if either A or B is true based on the information given to us in the diagram, so it cannot be A or B. C is false because all three of the angles in a triangle add up to 180°, and the equation in C only includes two angles. So the answer is D because it is the only statement we know to absolutely be true. Both angles three and four share one line (a line is 180°), so their sum must be 180°.
40(7.85) = 314
314 - (32.24 + 24.02 + 24.53) =
314 - 80.79 = 233.21 <== net pay