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2 years ago

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help pls The circumference of the hub cap of a tire is 80.1 centimeters. Find the area of this hub cap. Use 3.14 for pi. Use pen

cil and paper. If the circumference of the hub cap were smaller, explain how this would change the area of the hub cap.

2 answers:

katovenus [111]2 years ago

6 0

Answer:

510.25 cm².

Step-by-step explanation:

First, your gonna need to find the radius before continuing

80.1 ÷ 3.14 = 25.5

25.5 ÷ 2 = 12.75

Find the area

A=πr²

12.75² = 162.5

162.5 × 3.24 = 510.25

Liula [17]2 years ago

3 0

Answer: The area is 510.25 cm². If the circumference of the cap were smaller then the area would be smaller as well

Step-by-step explanation:

First, you must find the radius

<em>80.1 ÷ 3.14 = 25.5</em>

<em>25.5 ÷ 2 = 12.75 <---- radius</em>

Then from that, you find the area

A=πr²

<em>12.75² = 162.5</em>

<em>162.5 × 3.24 = 510.25</em>

<em></em>

<em>Hope this was helpful!</em>

<em></em>

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Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

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<u>Consider the given information:</u>

<u />

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<u>Solving the equation</u>

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SOLVE FOR X please help !!!!!!!!!!!

Julli [10]

think of it as half a circle which all equals up to 180 degrees

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so your answer is C) 118 degrees

hope that helped you out:)

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