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elixir [45]
3 years ago
8

Suppose a home improvement contractor is painting the walls and ceiling of a rectangular room. The volume of the room is 288 cub

ic feet. The cost of wall paint is $0.06 per square foot and the cost of ceiling paint is $0.16 per square foot. Let x, y, and z be the length, width, and height of a rectangular room respectively. Identify the room dimensions that result in a minimum cost for the paint and use these dimensions to find the minimum cost for the paint. Round your answer to the nearest cent.
Mathematics
1 answer:
ratelena [41]3 years ago
8 0

Answer:

The minimum cost is $17.30c

Step-by-step explanation:

Given

V = 288 --- Volume

C_1 = 0.06 --- cost of wall paint

C_2 = 0.16 ---cost of ceiling paint

Required

Minimum cost of paint

The volume is calculated as:

V =xyz

Substitute 288 for V

288 =xyz

Make z the subject

z = \frac{288}{xy}

The surface area is calculated as:

Area = 2(yz + xz) + xy

Because xy represent the dimension of the ceiling and the opposite of the ceiling (the floor) will not be painted. Hence, it does not require a coefficient of 2

The cost is:

C = 0.06 * 2(yz + xz) + 0.16 * xy

Substitute z = \frac{288}{xy}

C = 0.06 * 2(y*\frac{288}{xy} + x*\frac{288}{xy}) + 0.16 * xy

C = 0.06 * 2(\frac{288}{x} + \frac{288}{y}) + 0.16 * xy

C = 0.12(\frac{288}{x} + \frac{288}{y}) + 0.16 * xy

C = (\frac{34.56}{x} + \frac{34.56}{y}) + 0.16 * xy

C = (\frac{34.56}{x} + \frac{34.56}{y}) + 0.16 xy

Differentiate w.r.t x and y

C_x = -\frac{34.56}{x^2} + 0.16y

C_y = -\frac{34.56}{y^2} + 0.16x

By comparison: x = y

Set them equal to 0

C_y = -\frac{34.56}{y^2} + 0.16x=0

-\frac{34.56}{y^2} + 0.16x=0\\

Substitute x for y

-\frac{34.56}{x^2} + 0.16x=0

0.16x=\frac{34.56}{x^2}

Cross multiply

0.16x^3 = 34.56

x^3 = \frac{34.56}{0.16}

x^3 = 216

Take the cube root of both sides

x = \sqrt[3]{216}

x = 6

x=y= 6

Substitute 6 for x and for y in C = (\frac{34.56}{x} + \frac{34.56}{y}) + 0.16 xy

C = (\frac{34.56}{6} + \frac{34.56}{6}) + 0.16 * 6* 6

C = (\frac{2*34.56}{6}) + 5.76

C = 11.52 + 5.76

C = 17.28

C = 17.3 --- approximated

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Answer:

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Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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