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3 years ago

The perimeter of a triangle is 26 centimeters. Side a of the

Mathematics

1 answer:

boyakko [2]3 years ago

4 0

Answer:

side A 14, side b is11

Step-by-step explanation:

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Here are the 30 best lifetime baseball batting averages of all time, arranged in order from lowest to highest:

hichkok12 [17]

Answer:

Step-by-step explanation:

0.36|6=0.366

8 0

3 years ago

What is the value of this expression when a = 2 and b = -3 ? a^3 - b^3 / 5

saveliy_v [14]

Answer:

13 2/5

Step-by-step explanation:

a = 2 and b = -3

so the question asks whats.... a^3 - b^3/5

First we plug in the values of a and b

(2)^3 - (-3)^3 /5

Now we solve the ones in paranthesis first

(2)^3 = 8 because 2×2×2 and

-(-3)^3 forget about the - outside the parenthesis so

(-3)^3 = (-27) because (-3)×(-3)×(-3)

now we put it back together

8 -(-27)/5

the two minus become plus so

8 + 27/5

Now we solve it like fractions

8 and 27/5

simplify

13 and 2/5

Hope that helps!

5 0

3 years ago

PLEASE HELP!!!!

kondaur [170]

Add 6 to left middle and right
then, divide them all by 3

6 0

3 years ago

What is a 90 degree counter clockwise rotattion on a graph

mars1129 [50]

<h2><u>Answer:</u></h2><h2>90 Degree Rotation</h2><h2>When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.</h2>

<h2><u>Thank you</u></h2><h2><u>sunshinemadison101</u></h2>

7 0

3 years ago

Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a

Bond [772]

$f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x$

$f$ has critical points where $f'=0$ :

$3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi$

where $n$ is any integer. We get solutions in the interval $\left[0,\frac\pi3\right]$ for $n=0$ , for which $x=\frac\pi4$ .

At this critical point, we have $f\left(\frac\pi4\right)=3\sqrt2\approx4.243$ .

At the endpoints of the given interval, we have $f(0)=3$ and $f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098$ .

So we have the extreme values

$\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2$

$\min\limits_{x\in\left[0,\frac\pi3\right]}f=3$

8 0

3 years ago