Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+x=(-1)
Let x=0
y+x=(-1)
y+(0)=(-1)
y=(-1)
Let x=2
y+x=(-1)
y+(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
Answer:
45
Step-by-step explanation:
73+62=135
180-135=45
180 is the whole area of the triangle
Step-by-step explanation:
F respiratory system only remove carbon dioxide from the body
The question supplied is incomplete. The complete question is shown below:
The Gross national product (GNP) is the value of all the goods and services produced in an economy, plus the value of goods and services imported, less the goods and services exported. During the period of 1994-2004, the GNP of Canada grew about 4.8% per year, measured in 2003 dollars. In 1994, the GNP was $5.9 billion. Assuming this rate continues, in what year with the GNP reach $10 billion?
Answer:
2006
Step-by-step explanation:
Every year, the new GNP will become (100 + 4.8)% of that of the previous year. That is 104.8%, and equivalent of 1.048.
Let P(y) be the GNP after a period of y years.
After y years, the equation for calculating A(y) becomes
A(y)=5.9*(1.048)^y
Since A(y) = 10
10=5.9*(1.048)^y
10/5.9 =(1.048)^y
1.695=(1.048)^y
ln(1.695) = ln(1.048)^y
ln(1.695) = y ln1.048
y=ln1.695/ln1.048
y=11.26 years
1994 + 12 = 2006
Canada’s GNP will reach $10 billion in the year 2006
