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2 years ago

What does this multiple by 38 , 51 , 64 , 77 , 90

Mathematics

1 answer:

nadezda [96]2 years ago

3 0

Answer:

It's an arithmetic sequence. Instead of multiplying, you're adding 13. The answer is Tn=13n+25

Step-by-step explanation:

If you minus 38 from 51 (51-38), you get 13 and this 13 is constant throughout.

It's the same if you do (64-51).

Therefore 13 is our difference, we call it d.

Next you use the formula Tn=a+(n-1)d and substitute.

a is the first term of our sequence therefore it's a=38 and d=13.

We don't know n which is the number of terms.

When we sub its gonna be Tn=38+(n-1)(13)

And then you solve.

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What are the vertices of A'B'C if ABC is dilated by a scale factor of 2?

malfutka [58]

The vertices of A'B'C' if A(0, 10), B(8, 6), C(4, 2) is dilated by a scale factor of 2 are;

C. A'(0, 20), B'(16, 12), C'(8, 4)

<h3>Which method can be used to find the vertices of A'B'C'?</h3>

Given that triangle ABC is dilated by a scale factor of 2, we have;

A'B' = 2 × AB

A'C' = 2 × AC

B'C' = 2 × BC

Length of AB = √((8-0)^2 + (6-10)^2) = 4•√5

Length of AC = √((4-0)^2 + (2-10)^2) = 4•√5

Length of BC = √((8-4)^2 + (6-2)^2) = 4•√2

By multiplying the given coordinates by the scale factor, we have;

A' = 2 × (0, 10) = (0, 20)

B' = 2 × (8, 6) = (16, 12)

C' = 2 × (4, 2) = (8, 4)

A'B' = √((16-0)^2 + (12-20)^2) = 8•√5

A'C' = √((8-0)^2 + (4-20)^2) = 8•√5

B'C' = √((16-8)^2 + (12-4)^2) = 8•√2

Therefore when we have;

A'(0, 20), B'(16, 12), C'(8, 4), we get;

A'B' = 2 × AB

A'C' = 2 × AC
B'C' = 2 × BC

The correct option is therefore;

C. A'(0, 20), B'(16, 12), C'(8, 4)

Learn more about finding the distance between points on the coordinate plane here:

brainly.com/question/7243416

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5 0

2 years ago

I need help please either discord me the answer at F4deG0d#0988 or do it on here cause this is important.

algol13

Answer:

x= 12.5

2x = 25

4x = 50

6x = 75

Step-by-step explanation:

line CG is 180 degrees, so 12x + 30 = 180

x = 12.5

7 0

3 years ago

If £2000 is placed into a bank account that pays 3% compound interest per year,

klemol [59]

Answer:

£2,121.80

Step-by-step explanation:

To solve this problem, we can use the compound interest formula:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 3% into a decimal:

3% -> $\frac{3}{100}$ -> 0.03

Now, plug in the values:

$A=2,000(1+\frac{0.03}{1})^{1(2)}$

$A=2,121.80$

Your answer is £2,121.80

6 0

3 years ago

A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in

Andreyy89

So, she has 3hrs to grade all papers, for 35 students.. alrite.

the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6

now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.

now if we take 1/6 as the 100%, what is 1/5 in percentage then?

$\bf \begin{array}{ccllll}
rate&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{6}&100\\\\
\frac{1}{5}&x
\end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x}
\\\\\\
x=\cfrac{6\cdot 100}{5}\implies x=120$

so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.

8 0

3 years ago

Read 2 more answers

Solve each equation by substitution: y = 6x - 17 y= -4x +23

NISA [10]

Answer:

$y = 6x - 17 \\ y = - 4x + 23 \\ then \\ 6 x - 17 = - 4x + 23 \\ 10x = 40 \\ x = 4 \\ y = 7$

7 0

3 years ago