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Elis [28]
3 years ago
11

Please and thank you ​

Mathematics
1 answer:
ryzh [129]3 years ago
7 0

The answer is D. Y = 63 + 2 = 65

The given equation is y = x + 2, the height is given as 63. The height is the x value so you would replace x in the equation with 63 and solve for y.

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Bonjour est que quelqu'un pourrait m'aider svp pour cette exercice des mathématique Merci
Ivanshal [37]

(Le français n'est pas ma langue maternelle, alors je m'excuse d'avance si quelque chose n'est pas clair!)

Il me semble que le triangle MNP devrait ressembler à celui que j’ai attaché.

Les triangles MNP et MQR sont similaires, les côtés correspondants sont donc proportionnels:

\dfrac{MQ}{MN}=\dfrac{MR}{MP}=\dfrac{QR}{NP}

\implies\dfrac{2,5}6=\dfrac{MR}{5,7}=\dfrac{1,9}{NP}

\dfrac{2,5}6=\dfrac{MR}{5,7}\implies MR=2,375

\dfrac{2,5}6=\dfrac{1,9}{NP}\implies NP=4,56

3 0
4 years ago
Can someone help me pla
uranmaximum [27]
I believe the answer is B!

Hope this helped!
7 0
3 years ago
Read 2 more answers
The ratio of the interior angle measures of a triangle is 1:4:5. What are the angle measures?​
Vesna [10]
1x•4x•5x=180
10x=180
10/10x=180/10
X= 18
5 0
4 years ago
All of the edges of a regular triangular pyramid have length 12. A frustum of the pyramid has height half of that of the pyramid
vlada-n [284]

Answer:

1) The volume of the frustum is 27·(√3)·h

2) The surface area the frustum is 24·h + 54·√3

Step-by-step explanation:

1) A frustum of the regular triangular prism is a portion of the triangular prism

The length of the edge of the triangle prism = 12

The area of the triangular face, A = (√3/4)·a²

∴ A = (√3/4)·12² = 36·√3

When

The volume of the triangular prism, V = A·h = (36·√3)·h

By triangle proportionality theorem, the cross sectional area of the top half of the triangular prism =  (√3/4)·6² = 9·(√3)

The volume of the top half, V₂ = 9·(√3)·h

The volume of the frustum = V - V₂ = (36·√3)·h - 9·(√3)·h = 27·(√3)·h

The volume of the frustum = 27·(√3)·h

2) The surface area of the triangular side of the frustum is given as follows;

A = 36·√3- 9·(√3) = 27·(√3)

The surface area the frustum, F_A = 2×27·(√3) + 2 ×6 ×h + 12×h = 24·h + 54·√3

The surface area the frustum = 24·h + 54·√3

4 0
3 years ago
The product of 12 and 3
cestrela7 [59]

Answer:

36

Step-by-step explanation:

12 x 3 = 36

3 0
3 years ago
Read 2 more answers
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